How Many ATP Molecules Are Used in a Single Bicep Muscle Contraction?

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SUMMARY

During a single bicep muscle contraction, approximately 9.6 x 1020 molecules of ATP are required. This calculation is based on lifting a 10 kg weight 0.5 m, which requires 49 Joules of work. The energy released from ATP hydrolysis is 30.5 kJ per mole, leading to the conclusion that about 1.6 x 10-3 moles of ATP are necessary for this contraction. The final estimate rounds to roughly 1021 molecules of ATP utilized in a single twitch of the bicep muscle.

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  • Understanding of basic physics concepts such as work and energy
  • Knowledge of ATP hydrolysis and its energy release (30.5 kJ mol-1)
  • Familiarity with Avogadro's number (6.022 x 1023 mol-1)
  • Basic understanding of muscle physiology and contraction mechanisms
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  • Research the role of calcium ions in muscle contraction
  • Explore the biochemical pathways of ATP production, including Glycolysis and the Krebs Cycle
  • Investigate the energy requirements of different types of muscle contractions
  • Learn about the efficiency of ATP usage in various physical activities
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>> Calculate approximately how many molecules of ATP are required for a standard muscle like the biceps during the contraction phase of a single twitch.

I honestly do not even know where to begin here... I don't think he wants us to go through and just outline Glycolysis/Kreb's Cycle/ETC because that's just producing ATP in general, not for a specific contraction. And that's not saying how much is NEEDED...

I've looked around on the internet but can't really seem to come up with an answer. I know that calcium is needed but again, I can't figure out how much.

Does anyone think they could help me out? Thanks
 
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There are tons of different ways to approach this problem, from the very simple to the very involved. I'll go a very simple way. Let's take the bicep, for instance. Let's say you lift a 10kg weight 0.5m directly upward (using only your bicep somehow). This requires your bicep to do:
$$W = mgh = (10kg)(9.8m/s^2)(0.5m) = 49J$$
worth of work. ATP hydrolysis releases 30.5 kJ mol-1. This means that the number of moles of ATP required to do 49 J worth of work is:
$$\frac{49J}{30500J\cdot mol^{-1}}=1.6\times 10^{-3} mol$$
To get number of molecules, simply multiply by Avogadro's number:
$$(1.6\times 10^{-3} mol)(6.022 \times 10^{23} mol^{-1}) = 9.6 \times 10^{20}$$
So an order of magnitude estimate would be roughly 1021 molecules of ATP per muscle contraction.
 
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