How Many Bananas to Power a Light Bulb?

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SUMMARY

The discussion centers on calculating the number of bananas required to power a 100 W light bulb using the decay energy of potassium-40 (K-40) found in bananas. Each banana contains approximately 447.5 grams of potassium-40, derived from its potassium content of 358 mg per 100 grams. The half-life of potassium-40 is 1.248 billion years, leading to a decay constant (k) of 5.55×10^-10. To determine the exact number of bananas needed, one must incorporate the energy released during the decay of K-40 into the calculations.

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  • Familiarity with the decay constant calculation
  • Basic knowledge of energy conversion principles
  • Proficiency in using logarithmic equations
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  • Explore the implications of using biological materials for energy generation
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Homework Statement



If all of the energy from decay of the 40-K in one banana could be captured and converted into electrical energy, how many bananas would be needed to power a 100 W light bulb?

There is 358 mg potassium-K per 100 grams of banana

half life of potassium-40 is 1.248(3)×109 y

Homework Equations



ln(A/Ao)=-kt
e=mc2
k= (0.693/half-life)

The Attempt at a Solution



If a banana weighs 125 grams on average then there is 447.5 grams of potassium-40 in one banana.

(358)(1.25) = 447.5g
- - - - - - - - - - - - - -
k=(0.693/1.248(3)×10^9 y) = 5.55×10^-10

ln(A/Ao)=-kt
k = 5.55×10^-10
Ao = 447.5 g
t=?
 
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That's 447.5 mg of K-40

You'll need an equation that includes the energy of decay of the isotope.
 
Last edited:

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