How Many Batting Orders Can Include the Pitcher Batting Last?

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SUMMARY

The discussion centers on calculating the number of possible batting orders for a baseball team where the pitcher bats last. Given a starting lineup of nine players, the calculation involves arranging the remaining eight players in the first eight positions, resulting in 8! (factorial) arrangements. The final batting order is determined by multiplying the number of arrangements (8!) by the fixed position of the pitcher at the end, leading to a total of 72 unique batting orders.

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  • Understanding of basic combinatorial mathematics
  • Familiarity with factorial notation (n!)
  • Knowledge of baseball positions and lineup structure
  • Basic understanding of permutations
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  • Study combinatorial mathematics and factorial calculations
  • Learn about permutations and their applications in sports lineups
  • Explore advanced baseball statistics and lineup optimization techniques
  • Investigate the role of batting order in game strategy and performance analysis
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i cannot get the question since i don't know how to play baseball...
this is the question...
The manager of a baseball team has picked the nine players for the starting lineup. In how many ways canhe set the batting order so that the pitcher bats last?
 
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assume that the pitcher is one of the 9 in the starting line up and then go from there.
 
happyg1 said:
assume that the pitcher is one of the 9 in the starting line up and then go from there.

so the answer would be 9(players) * 8(positions) * 1(nineth - pitcher will be the last) = 72
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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