How many days does it rain in May?

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SUMMARY

The discussion centers on the probability of rain in May, with a survey indicating it rains on average 15 out of 30 days, leading to a conditional probability P(R|M) of 1/2. The Weather Service forecasts accurately 2/3 of the time, implying that it does not rain 2/3 of the time. The participants analyze the probabilities of the Weather Service predicting dry weather and the likelihood of rain on days without an umbrella. The correct interpretation of these probabilities is crucial for accurate forecasting and personal planning.

PREREQUISITES
  • Understanding of conditional probability, specifically P(A|B)
  • Familiarity with basic probability equations, such as P(A n B) = P(A|B) * P(B)
  • Knowledge of weather forecasting accuracy metrics
  • Basic comprehension of statistical surveys and averages
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  • Research "Bayesian probability" to deepen understanding of conditional probabilities
  • Explore "Weather forecasting accuracy metrics" to evaluate prediction reliability
  • Study "Statistical surveys and their implications" for insights on data interpretation
  • Learn about "Probability distributions" to understand variations in weather patterns
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Students studying probability theory, meteorologists analyzing weather patterns, and anyone interested in understanding the implications of weather forecasts on daily planning.

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Homework Statement



A survey concludes that it in average rains 15 of 30 days in may.

Thusly P(R|M) = 1/2

Where M is May and R is rain.

The Weatherservice forcasts fits 2/3 of the time. Thus it does not rain 2/3 of the time.

I bring umbrella with me every day the promise and 1/3 of the days where do not perdict rain.


1) What is the prob that that Weather Service promises dry weather in a day in May?

2) What is the prob that it rains on a day where I did not bring my umbrella?

Homework Equations



P(A|B) = P(A n B)/P(B)

The Attempt at a Solution




By using the formula in condition prob.

I get 1)

P(R|M) = 1/2 P(R) = P(R) = 1 - P(does not rain) = 1 - 1/3 = 2/3

Thus 1/2 = P(R n M) / P(R) -> 1/2 = (R n M)/ (2/3) = 1/3


I am not sure about 2 ?

2) P = 1/3 * 2/3 = 2/9 ?


Hope there is someone who would take a look at it?
 
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Scienceboy1776 said:

Homework Statement



A survey concludes that it in average rains 15 of 30 days in may.

Thusly P(R|M) = 1/2

Where M is May and R is rain.

The Weatherservice forcasts fits 2/3 of the time. Thus it does not rain 2/3 of the time.

I bring umbrella with me every day the promise and 1/3 of the days where do not perdict rain.


1) What is the prob that that Weather Service promises dry weather in a day in May?

2) What is the prob that it rains on a day where I did not bring my umbrella?

Homework Equations



P(A|B) = P(A n B)/P(B)

The Attempt at a Solution




By using the formula in condition prob.

I get 1)

P(R|M) = 1/2 P(R) = P(R) = 1 - P(does not rain) = 1 - 1/3 = 2/3

Thus 1/2 = P(R n M) / P(R) -> 1/2 = (R n M)/ (2/3) = 1/3


I am not sure about 2 ?

2) P = 1/3 * 2/3 = 2/9 ?


Hope there is someone who would take a look at it?

Are you saying that P(Rain|forcast rain) = P(no rain|forecast no rain) = 2/3, or are you saying P(forecast rain|rain) = P(forecast no rain|no rain) = 2/3? Do you see the difference? Anyway, your conclusion "Thus it does not rain 2/3 of the time" is wrong; do you see why?

Your sentence "I bring umbrella with me every day the promise and 1/3 of the days where do not perdict rain" is so badly written as to be almost incomprehensible; do you mean that you "bring an umbrella whenever the forecast is for rain and also 1/3 of the time when the prediction is for no rain"?
 
By the way, May has 31 days in it, not 30.

"Thirty days hath September, April, June, and November..."
 

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