How many different hands can be dealt in this variant of Poker?

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In a variant of Poker where each player is dealt a hand of 6 cards, the calculation for the number of possible hands featuring three pairs involves combinatorial mathematics. The initial calculation of 1001 different hands is derived from the formula 13C3 + 12C3 + 11C3 + ... + 3C3, representing the selection of three distinct card values. However, this does not account for the suit variations, which must be multiplied by the number of combinations of suits for each pair, resulting in a more complex total. A systematic approach is essential for accurate calculations.

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In a varient of Poker each player is dealt a hand of 6 cards from a standard pack How many hands are there of each of the following types?

Three pairs: Two cards of the same value. another 2 of a different value, and a 3rd paid of a third value. i.e Q(clubs) Q(diamonds) 6(hearts) 6(diamonds) 4(spades) 4(hearts)

..

For my attempt I started with 13C3 + 12C3 +11C3 ... + 3C3 = 1001 different hands

But this hasn't accounted for the different variation of suits, threre are 6 possible pairs of suits, so i multiply 1001 by 6?

thanks for any help!
 
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Hi Firepanda! :smile:

Firepanda said:
For my attempt I started with 13C3 + 12C3 +11C3 ... + 3C3 = 1001 different hands

erm … 13C3 is the number of ways of choosing 3 cards out of 13 … but what did you think was the reason for adding 12C3 etc?

Be systematic. One step at a time.

First step: there have to be three different numbers (eg 2 5 Q).

Second step: for each number, there have to be 2 cards of that number.

Try it that way! :smile:
 

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