How many electrons are involved in a lightning flash

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SUMMARY

A typical lightning flash delivers approximately 35 coulombs of negative charge from cloud to ground. To determine the number of electrons involved, one must use the charge of a single electron, which is -1.6 x 10-19 coulombs. By dividing the total charge of -35 coulombs by the charge of one electron, the calculation yields approximately 2.19 x 1020 electrons. This confirms that a lightning flash consists of a substantial number of electrons, not just a fraction.

PREREQUISITES
  • Understanding of electric charge and its measurement in coulombs
  • Familiarity with the charge of an electron (-1.6 x 10-19 coulombs)
  • Basic knowledge of unit conversion and dimensional analysis
  • Concept of negative charge in electrical phenomena
NEXT STEPS
  • Research the relationship between charge, current, and time in electrical circuits
  • Learn about the physics of lightning and its electrical properties
  • Explore the concept of charge quantization and its implications in physics
  • Investigate the effects of electric fields on charged particles
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Students studying physics, educators teaching electrical concepts, and anyone interested in the science behind lightning and electrical charge.

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A typical lightning flash delivers about 35 C of negative charge from cloud to ground. How many electrons are involved?


Im not extactly sure how to approach this question. it should be an easy one since it's one of the first problems from the book.

Im thinking i might need to use this formula: F = qE

since I am trying to find the force right? please help, i am really confuse
 
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Nope, how much charge does an electron have in coulombs? so if you have 35 coulombs then how many electrons do you have?

nothin to do with forces
 
-1.6 x 10^{-19} electron per coulombs right? so (-1.6 x 10^-19)*35 = -56 X 10^{-19}
 
Reality check: how can a lightning flash contain only a tiny fraction of an electron? :eek:

Think of the electron charge as having units as follows:

-1.6 \times 10^{-19} \frac{coulombs}{electron}

Now, how should you multiply or divide this with 35 coulombs, in order for the result to have units of "electrons"?

Actually, the total charge really should be given as -35 coulombs. Since the lightning flash is made up of electrons, it has to be negatively charged. That takes care of the other problem with your answer: it gives a negative number of electrons!
 

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