How many grams of FeCr2O7 are needed for 44.0 grams of CO2?

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Discussion Overview

The discussion revolves around a stoichiometry problem involving the reaction of iron (II) dichromate with potassium carbonate to produce carbon dioxide. Participants explore the calculation of the mass of iron (II) dichromate required to yield 44.0 grams of CO2, addressing aspects of chemical equations and molar mass.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant initially calculated 79.925 grams of iron (II) dichromate but later revised their answer to 109.92 grams based on stoichiometric relationships.
  • Another participant questioned the existence of iron (II) dichromate, suggesting it might be a misinterpretation of the problem.
  • A later post corrected the molar mass of iron (II) dichromate to 271.85 grams and calculated the required mass to be 135.93 grams.
  • Participants discussed the use of proportions in stoichiometric calculations, with one asserting that they always use proportions for such problems.

Areas of Agreement / Disagreement

There is no clear consensus on the correct mass of iron (II) dichromate required, as participants have provided different calculations and interpretations. Some participants agree on the use of proportions, while others focus on different methods of calculation.

Contextual Notes

Participants express uncertainty regarding the correct interpretation of the chemical species involved and the calculations of molar masses. There are also unresolved issues regarding the initial misinterpretation of the problem and the accuracy of the molar mass used.

Who May Find This Useful

This discussion may be useful for students working on stoichiometry problems in chemistry, particularly those dealing with reactions and molar mass calculations.

Quincy
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Homework Statement


4FeCr2O7 + 8K2CO3 + O2 --> 2Fe2O3 + 8K2CrO4 + 8CO[sub2[/sub]

How many grams of iron (II) dichromate are required to produce 44.0 grams of carbon dioxide?


Homework Equations





The Attempt at a Solution



79.925 grams of iron (II) dichromate
 
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Too low. Show your work.

Strange reaction and strange reactant though. If you ask me, there is no such thing as iron (II) dichromate.
 
Nevermind my first answer, I misinterpreted the problem, this is my new answer:

Since it takes takes 4 moles of iron (II) dichromate to produce 8 moles of carbon dioxide, it would take 0.5 moles of iron (II) dichromate to produce 1 mole of carbon dioxide (1 mole of CO2 = 44 g). And 0.5 moles of iron (II) dichromate = 109.92 grams of iron (II) dichromate (answer).

-- I don't really know what I'm doing btw; these are questions from my pre-AP Chem summer assignment and I'm bookless and haven't done any chemistry for about 1 1/2 years.
 
Your approach is OK, just numbers are wrong. What have you used for molar mass of iron (II) dichromate?
 
molar mass of iron (II) dichromate = 271.85 g

271.85/2 = 135.93 g... nevermind my other answer, is 135.93 g correct?
 
135.9 g is OK. Sorry for the late answer.
 
molar mass 4FeCr2O7 = 1087.4 g

molar mass 8CO2 = 352.08 g

1087.4/352.08 = x/44 ~ x = 135.9 g

^ Is it possible to use proportions for these type of problems?
 

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