Discussion Overview
The discussion revolves around determining the number of ions present in one formula unit of the compounds HI, HBr, and N2S5. Participants explore concepts related to dissociation in aqueous solutions versus gases, as well as the nature of molecular compounds.
Discussion Character
- Homework-related
- Conceptual clarification
- Debate/contested
Main Points Raised
- One participant suggests that HI(aq) contains 2 ions (H+ and I-) due to dissociation in solution.
- Another participant questions why HBr(g) would not also yield 2 ions, indicating confusion about its dissociation behavior as a gas.
- There is a discussion about the process that creates ions in HI(aq), with a focus on dissociation.
- Some participants assert that HBr(g) does not dissociate, leading to the conclusion that it has only molecules present, not ions.
- Regarding N2S5, there is uncertainty about whether it exists and how many ions it would have, with suggestions that it might also have 0 ions due to lack of dissociation.
- One participant proposes that if N2S5 were to be considered, it might be treated as having 0 ions, while another speculates about its composition.
- There is a mention of N2S5 being a binary molecular compound, but its existence is contested, leading to further confusion.
Areas of Agreement / Disagreement
Participants express differing views on the dissociation of HBr(g) and the existence of N2S5, indicating that multiple competing views remain and the discussion is unresolved.
Contextual Notes
Participants note the confusion surrounding the nature of molecular compounds and their dissociation in different states (aqueous vs. gas). The existence of N2S5 is questioned, and its implications for ion count remain unclear.