How many kilograms of sand have a total surface area of 6 m^2?

  • Thread starter Thread starter icesalmon
  • Start date Start date
  • Tags Tags
    Mass Silicon
Click For Summary

Homework Help Overview

The discussion revolves around calculating the mass of sand required to achieve a total surface area of 6 m², specifically in the context of using sand for wastewater treatment. The sand grains are modeled as spheres with a given radius, and the problem involves understanding the relationship between surface area, volume, and mass based on the properties of the material.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the surface area of the sand grains and the total surface area required. There are attempts to calculate the number of grains based on the surface area of individual grains and the total surface area provided. Questions arise regarding the correct formulas for surface area and volume, as well as the implications of density on mass calculations.

Discussion Status

The discussion is active, with participants providing various approaches to calculate the number of grains of sand needed and the corresponding mass. Some participants have offered guidance on how to calculate the surface area of a single grain and how to relate that to the total surface area. There is a recognition of the need to clarify certain mathematical relationships and units involved in the calculations.

Contextual Notes

Participants note potential confusion regarding the units of measurement, particularly when converting between cubic meters and cubic microns. There is also mention of the density of the sand and its relevance to determining mass, as well as the importance of ensuring correct formulas are applied throughout the problem-solving process.

icesalmon
Messages
270
Reaction score
13

Homework Statement



As part of the initial treatment for waste water from an industrial site, you will be running the afluent through a sand filter. The filtering ability of the sand in this filter is roughly proportional to the surface area of the sand enclosed. The grains of fine sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide. A solid cube of this material with a volume of 1 m3 has a mass of 2500 kg. You have determined that the total surface area (the total area of all the individual grains) is equal to the surface area of a cube 1 meters on an edge.

What is the mass of the sand in kilograms

Homework Equations


Volume of sphere
Surface Area of Cube

The Attempt at a Solution


The Volume of a sphere is (4pir3)/3 and the surface area of a cube is 4a2 and the surface area of a cube 1 meter on an edge is 1m3 I also have the number of particles in a sphere (4/3)pi(50μm)3 and I have 6m2/(4pi(50μm)2)

I don't know what this information is doing geometrically or what it has to do with finding the mass of the sand but it was written down and I needed help filling in the blanks.
 
Last edited:
Physics news on Phys.org
Since you have the total surface area, and you know it is the surface of a number of spheres with the given radius, you can find the number of spheres. Then, can you find the total volume of the spheres?
 
Are you sure you have the correct formula for surface area?
 
for a cube it is 6*(a)(a) where a is the length of the edge and my a = 1m -> 6meters2
for the sphere I am using the volume and the surface area, both of which I am fairly sure are correct.
/edit you were right, my formulas were switched up. my mistake
 
voko said:
Since you have the total surface area, and you know it is the surface of a number of spheres with the given radius, you can find the number of spheres. Then, can you find the total volume of the spheres?

i'm not sure how to do this part, and which surface area are you talking about here, the cube or the sphere? when you say spheres you mean grains of sand, right?

I feel I should multiply the surface area of one of the figures by the number of spheres to find the total volume of the spheres, so I have the surface area and I need the number of spheres. Which I think I can find with each sphere has an average radius of 50μm and I find out how many of them cover the surface area of the sphere/cube by multiplying by the surface area of that object so either 4/3pi(50μm)3 or for the cube with 50μm*1m3 maybe?
 
The total area of the grains of sand is given to be equal to the area of the 1m cube. This is what you should use to find the number of grains.
 
okay, so I have 6(50x10-3m)
 
icesalmon said:
okay, so I have 6(50x10-3m)

What is this?
 
the surface area of a cube 1m on an edge multiplied by the average radius of one grain of SiO2
 
  • #10
icesalmon said:
the surface area of a cube 1m on an edge multiplied by the average radius of one grain of SiO2

And what does that mean, anyway?

Note also that the radius of grains is 50 micrometers, no millimeters as you have it.
 
  • #11
If you can calculate the surface area of 1 grain of sand, can't you then figure out how many grains of sand it takes to equal 6 m^2? I don't know what multiplying the surface area of a 1m cube by the radius of a grain of sand gives you.
 
  • #12
I wasn't sure either, so how many times does 50 micrometers go into 6 square meters
so I've got 6m2/(50x10-6m) = 120,000m
Should I multiply this value by the mass of each sand grain?
 
Last edited:
  • #13
Stop trying things at random. Think: what is the number of grains so that their total surface are is 6 square meters? What is the surface area of one grain?
 
  • #14
What is the volume of 1 grain of sand if its radius is 50 microns?
What is the mass of 1 grain of sand, given that its density is 2500 kg per cubic meter?
What is the surface area of 1 grain of sand if its radius is 50 microns?
How many sand grains is required if their total surface area is 6 m^2?
What is the mass of these sand grains?
 
  • #15
voko said:
Stop trying things at random. Think: what is the number of grains so that their total surface are is 6 square meters? What is the surface area of one grain?
the surface area of one grain, since they are spheres with radius 50microns, is (4pi(50x10-6)2
 
Last edited:
  • #16
Chestermiller said:
What is the volume of 1 grain of sand if its radius is 50 microns?
What is the mass of 1 grain of sand, given that its density is 2500 kg per cubic meter?
What is the surface area of 1 grain of sand if its radius is 50 microns?
How many sand grains is required if their total surface area is 6 m^2?
What is the mass of these sand grains?

the volume of one grain of sand is (4pi(50x10-6)3)/3
I have no idea how to find out the mass of 1 grain of sand if it's density is 2500kg/m3
the surface area of 1 grain of sand is 4pi(50x10-6)2
 
  • #17
What is density?
 
  • #18
mass/unit volume but that mass is not per 50microns it is for 1 cubic meter, so I think I have to use dimensional analysis to convert cubic meters to 50 microns which I don't have any idea how to do because I have different powers of meters.
 
  • #19
How many cubic microns= 1 cubic meter? :) google it up...
 
  • #20
1x1018
 
  • #21
mass/volume=density
plug and chug.
 
  • #22
m/1x1018 = 2500kg/m3
m = (2500kg/m3)*1x1018microns3
 
  • #23
icesalmon said:
m/1x1018 = 2500kg/m3
m = (2500kg/m3)*1x1018microns3

Not in micron3 its 1x10-18m3
:wink:
 
  • #24
I thought I found how many cubic microns were in 1 cubic meter. Why aren't those the units that I'm using?
 
  • #25
Think about the volume of 1 grain of sand. It's 4*pi*(50*10^-6)^3. What are the units of this volume?
 
  • #26
icesalmon said:
I thought I found how many cubic microns were in 1 cubic meter. Why aren't those the units that I'm using?
Then you also found that 1 cubic micron = 1x10^ -18 meters
If you use it in microns wouldn't
m = (2500kg/m3)*1x1018microns3
be in units of kg*micron3/m3
On the other hand:
m = (2500kg/m3)*1x10-18m3
the m3 cancels out in numerator and denominator leaving kg behind.
 
  • #27
so the mass of one grain of sand of SiO2 is 2.5x10-15kg
now I need to figure out how many grains of sand with a volume of (4pi(50microns)^3)/3 go into one cubic meter
 
Last edited:
  • #28
so I've got 4(2500x10^-18m^3)/3
 
  • #29
icesalmon said:
so I've got 4(2500x10^-18m^3)/3

Something isn't right. R = 50 microns = 50*10^-6 meters

Volume = (4/3)pi*R^3 = (4/3)*pi*(50*10^-6)^3 m^3 / grain of sand

Surface Area = 4*pi*R^2 = 4 * pi * (50*10^-6)^2 m^2 / grain of sand

Sand has a density of 2500 kg / m^3

You want to find out:

1. how many grains of sand have a total surface area of 6 m^2, and then
2. how many kg of sand this is equivalent to.

Knowing the surface area of 1 grain of sand, how many grains have a total surface area of 6 m^2?

Knowing how many grains of sand, what is the total volume of sand?

Knowing the total volume of the sand, what is its mass?

Answer these questions, and you will have solved the problem from the OP.
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
18K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 18 ·
Replies
18
Views
6K