How many moles of ions are present in 250mL of 4.4 M solution of sodium sulfate?

  • Context: Chemistry 
  • Thread starter Thread starter Asian Girl
  • Start date Start date
  • Tags Tags
    Ions Moles
Click For Summary
SUMMARY

The discussion revolves around calculating the number of moles of ions in a 250 mL solution of 4.4 M sodium sulfate (Na2(SO4)). The correct calculation reveals that the solution contains 3.3 moles of ions, derived from the dissociation of sodium sulfate into three ions: two sodium ions (Na+) and one sulfate ion (SO4^2-). Additionally, a related question discusses the production of hydrogen gas (H2) from the electrolysis of water, emphasizing the need to understand the electron transfer involved in the reaction.

PREREQUISITES
  • Understanding of molarity and its calculation
  • Knowledge of ionic dissociation in aqueous solutions
  • Familiarity with the concept of moles and Avogadro's number
  • Basic principles of electrolysis and chemical reactions
NEXT STEPS
  • Study ionic dissociation and its impact on solution concentration
  • Learn about Avogadro's number and its application in stoichiometry
  • Research electrolysis of water and the stoichiometry of gas production
  • Explore the concept of electron transfer in redox reactions
USEFUL FOR

Chemistry students, educators, and anyone preparing for competitive exams like the Olympiad, particularly those focusing on stoichiometry and electrochemistry.

Asian Girl
Messages
35
Reaction score
0
I thought this is a pretty easy problem and I can't believe I did it wrong. What did I do wrong?

How many moles of ions are present in 250mL of 4.4 M solution of sodium sulfate?

Here what I did:
250 mL = .25 L
mol Na2(SO)4 = MV = 4.4 * .25 = 1.1 mol

but the answer was 3.3 mol
 
Physics news on Phys.org
Because the question asks how many ions are present, you need to multiply the moles of sodium sulfate by the number of ions it breaks down into in water.

In this case, I believe the Na2(SO)4 will dissociate to make two Na+ ions and one (SO)4 ion (total of 3 ions).
 
altegron said:
Because the question asks how many ions are present, you need to multiply the moles of sodium sulfate by the number of ions it breaks down into in water.

In this case, I believe the Na2(SO)4 will dissociate to make two Na+ ions and one (SO)4 ion (total of 3 ions).

Thanks
 
Another one:
Water can be decomposed by the passage of an electric current according to the equation 2H2O (l) ---> 2H2 (g) + O2 (g)
How many moles of H2 (g) can be produced from the passage of 4.8*10^21 electrons?

I solved:
4.8*10^21 / 6.022*10^23 * 2 = 1.6*10^-2 mol

What did I do wrong?
 
How many electrons needed per each H2 molecule?

Borek
 
Last edited by a moderator:


yea really I need answer for her question fast :S I have OLYMPIAD Tomorrow. Thanks :smile:
 


Which question?
 
Last edited by a moderator:


ElectroBoss said:
yea really I need answer for her question fast :S I have OLYMPIAD Tomorrow. Thanks :smile:
I'm sorry, but this forum does not work that way. Please read the forum rules first.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
12K
  • · Replies 10 ·
Replies
10
Views
15K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K