Error Analysis for Moles of Calcium Ions in 250mL

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SUMMARY

The discussion focuses on error analysis in the context of calculating moles of calcium ions in a solution. The initial calculation indicates that the moles of calcium ions in 10 mL is 6.0 x 10-4 ± 0.5 x 10-5 mols. When scaling this value to 250 mL, it is established that both the moles and the associated error must be multiplied by the same scaling factor of 25, resulting in a new error value that reflects the increased volume.

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Just a quick question about error analysis.

Moles of Calcium ions in 10 mL = 6.0 x 10-4 ± 0.5 x 10^-5 mols

I'm suppose to scale this number to Moles of Calcium ions in 250mL.
So when I multiply by 25, do I multiply the error value as well? Or does it remain the same?
 
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Number of moles does change, so error does as well.
 

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