How many moles of ions are present in 250mL of 4.4 M solution of sodium sulfate?

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Discussion Overview

The discussion revolves around calculating the number of moles of ions present in a sodium sulfate solution and also touches on a separate problem regarding the production of hydrogen gas from water decomposition. The scope includes mathematical reasoning and problem-solving related to chemistry concepts.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the moles of sodium sulfate in a 250 mL solution and arrives at 1.1 mol, but questions why the answer is stated as 3.3 mol.
  • Another participant explains that sodium sulfate dissociates into three ions (two Na+ and one SO42-), suggesting that the moles of ions should be calculated by multiplying the moles of sodium sulfate by 3.
  • A separate participant presents a problem about the decomposition of water and calculates the moles of hydrogen gas produced from a given number of electrons, but questions their own calculation.
  • There is a query about how many electrons are needed to produce one molecule of hydrogen gas, with a response indicating that 2 electrons are required.
  • Some participants express urgency for answers due to an upcoming Olympiad, indicating a need for quick responses.

Areas of Agreement / Disagreement

There is no consensus on the initial calculation of moles of ions, as one participant's calculation conflicts with another's explanation of dissociation. The discussion about the hydrogen gas problem also remains unresolved, with participants seeking clarification.

Contextual Notes

The calculations depend on the understanding of dissociation in solutions and the stoichiometry of chemical reactions, which may not be fully detailed in the posts. There are also unresolved mathematical steps in the hydrogen gas problem.

Asian Girl
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I thought this is a pretty easy problem and I can't believe I did it wrong. What did I do wrong?

How many moles of ions are present in 250mL of 4.4 M solution of sodium sulfate?

Here what I did:
250 mL = .25 L
mol Na2(SO)4 = MV = 4.4 * .25 = 1.1 mol

but the answer was 3.3 mol
 
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Because the question asks how many ions are present, you need to multiply the moles of sodium sulfate by the number of ions it breaks down into in water.

In this case, I believe the Na2(SO)4 will dissociate to make two Na+ ions and one (SO)4 ion (total of 3 ions).
 
altegron said:
Because the question asks how many ions are present, you need to multiply the moles of sodium sulfate by the number of ions it breaks down into in water.

In this case, I believe the Na2(SO)4 will dissociate to make two Na+ ions and one (SO)4 ion (total of 3 ions).

Thanks
 
Another one:
Water can be decomposed by the passage of an electric current according to the equation 2H2O (l) ---> 2H2 (g) + O2 (g)
How many moles of H2 (g) can be produced from the passage of 4.8*10^21 electrons?

I solved:
4.8*10^21 / 6.022*10^23 * 2 = 1.6*10^-2 mol

What did I do wrong?
 
How many electrons needed per each H2 molecule?

Borek
 
Last edited by a moderator:


yea really I need answer for her question fast :S I have OLYMPIAD Tomorrow. Thanks :smile:
 


Which question?
 
Last edited by a moderator:


ElectroBoss said:
yea really I need answer for her question fast :S I have OLYMPIAD Tomorrow. Thanks :smile:
I'm sorry, but this forum does not work that way. Please read the forum rules first.
 

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