The discussion focuses on calculating the number of moles of NH3 in a solution of 0.2 M NH3 mixed with 2 M NH4NO3. The solution volume is 2 mL, and the final answer is required in millimoles (mmol). The correct calculation involves determining the ratio of NH3 to NH4NO3, which is 1:10, leading to the conclusion that there are 0.0364 mmol of NH3 in the supplied solution.
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everscern said:Homework Statement
How many moles of NH3 are in 2ml of supplied solution: 0.2 M NH3 in 2 M Nh4NO3
Ans to be given in mmol
Homework Equations
Concentration = mol/ L
The Attempt at a Solution
Ratio of NH3 : NH4NO3 = 1: 10
2 / 11 = 0.182 ml
0.2 mol/L * 1L/ 1000ml * 0.182 ml * 1000 = 0.0364 mmol