Moles Ratio: Calculate Heat Generated by N2 & H2

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    Homework Moles Ratio
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SUMMARY

The forum discussion focuses on calculating the heat generated from the reaction of nitrogen (N2) and hydrogen (H2) to form ammonia (NH3) using the reaction enthalpy of -46.11 kJ/mol. Given 10 moles of N2 and 35 moles of H2, with only 10% of N2 reacting, the calculation shows that 2 moles of NH3 are produced. Consequently, the total heat generated is -92.22 kJ, confirming the accuracy of the calculations presented.

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Homework Statement



Given:

(1/2) mol N2 + (3/2) mol H2 -> NH3 change in H = -46.11 kJ/mol

If the number of moles of N2 are changed to 10 and the number of moles of H2 to 35,
how much heat is generated if only 10% of the Nitrogen reacts?


The Attempt at a Solution



After setting up a ratio, I find that 10 moles of N2 can produce 20 moles of NH3. Thus, 10% of the N2 means 10% of the NH3, so 2 moles of NH3 are produced.

I multiple 2 by the original energy to achieve -92.22kJ.

Did I do this correctly?
 
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Appears to be correct.
 

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