How Many Sets of Four Consecutive Integers Have a Product Under 100,000?

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SUMMARY

The discussion focuses on determining how many sets of four consecutive integers have a product less than 100,000. The key insight is that if the product of integers a, b, c, and d is less than 100,000, then any set of four consecutive integers preceding it will also have a product below this threshold. The approach involves solving the equation b^4 = 100,000 to find the maximum value of b, which leads to identifying the first set of integers whose product meets or exceeds 100,000. The conclusion emphasizes that the number of valid sets is simply one less than the first set that reaches or exceeds this product.

PREREQUISITES
  • Understanding of basic algebra and inequalities
  • Familiarity with the concept of consecutive integers
  • Knowledge of polynomial equations, specifically b^4
  • Basic problem-solving skills in number theory
NEXT STEPS
  • Explore polynomial equations and their applications in number theory
  • Learn about the properties of consecutive integers and their products
  • Investigate methods for estimating the product of consecutive integers
  • Study combinatorial approaches to counting sets of integers
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Mathematicians, educators, students studying number theory, and anyone interested in combinatorial mathematics will benefit from this discussion.

rocomath
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How many sets of four consecutive integers are there such that the product of the four integers is less than 100,000?

Set_1=1,2,3,4
Set_2=5,6,7,8
Set_3=9,10,11,12

Set_n=a\cdot b\cdot c\cdot d<100,000

Okay, I know I could continue with my Sets, but there has got to be a more logical approach. Help start me off please! I've already plugged and chugged it and found the amount of sets, but I want a better approach.
 
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Why did you skip over 2,3, 4, 5? Or 3, 4, 5, 6? Do you see that if, for some a, b, c, d, their product is less than 100000, so is the product of any 4 consecutive integers less than that?

How large must a, b, c, d be so that their product IS 100000? Since a, b, c, d are consecutive, they are relatively close to each other so their product must be close to b4. Solve b4= 100000 and look for a, b, c, d close to that. Do you see that the number sets of 4 consectutive integers whose product is less than 100000 is simply the "a-1" of the first a, b, c, d whose product is equal to or greater than 100000?

(The answer is surprisingly low!)
 
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Ah crap, I completely forgot about 2,3,4,5 etc :( Now my answer is completely wrong ...

Ok let me go back to this problem.
 
You knew your answer was not right to begin with- that's why you asked the question!

Have you payed any attention to the rest of my response? It took me about 2 minutes to solve that problem (counting the time I spent sharpening my pencil).
 
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