How many steps does Euler's method take to achieve a specific error tolerance?

  • Thread starter Thread starter roam
  • Start date Start date
  • Tags Tags
    Method
Click For Summary
Euler's method requires a significant number of steps to achieve a specific error tolerance, as demonstrated in the discussion. The user calculated that 7760 steps are needed to reduce the error to match that of the 4th order Runge-Kutta method. This calculation was based on the error formula e_n ≤ k/n, where k was derived from the initial error estimate. The validity of this approach was confirmed, suggesting that the number of steps is indeed reasonable. The discussion emphasizes the importance of verifying calculations using computational tools for accuracy.
roam
Messages
1,265
Reaction score
12

Homework Statement



I need some help with the last part of the following problem:

http://img834.imageshack.us/img834/8366/eulere.jpg

The Attempt at a Solution



My approximation to the solution to the IVP at t=-0.8 using 1 step of the Euler's method was:

x(-0.8)=0.8

Whereas the approximation with 1 step of 4th order Runge-Kutta method was:

x(-0.8)=0.8214

And since the exact solution is

x(-0.8) = e^{-0.8 +1} -2 \times (-0.8) -2 = 0.8214027582

the error in Euler's method would be

|0.8214027582-0.8| =0.0214027582

And the error for Runge-Kutta is

|0.8214027582-0.8214| =2.7582 \times 10^{-6}

I'm stuck here. So how many steps does Euler's method take to produce an answer with an error no larger than 2.7582 x 10-6 (the error of Runge-Kutta)?

I tried to use the following equation:

e_n \leq \frac{k}{n}

Where k is a constant and n is the number of steps and en is the error. I then tried to solve for the constant bu substituting in the values from Euler's method:

0.021402758 = \frac{k}{1} \ \implies k =0.021402758

Then substituting in the new error

2.7582 \times 10^{-6}=\frac{0.021402758}{n} \ \implies n = 7760

But doesn't 7760 steps seem too much? Where did I go wrong? I appreciate it if anyone could help me with this problem.
 
Last edited by a moderator:
Physics news on Phys.org
7760 seems to be OK. You could confirm this using a program or a spreadsheet with Δt = (0.2 / 7760) to see if it corresponds with your answer.
 
Last edited:
But I am wondering if I've even used the correct method for finding the number of steps?
 
roam said:
I tried to use the following equation:
e_n \leq \frac{k}{n}
roam said:
But I am wondering if I've even used the correct method for finding the number of steps?
What was the source of the error equation you used, class notes, a textbook, ... ?
 
rcgldr said:
What was the source of the error equation you used, class notes, a textbook, ... ?

It's from a textbook...

Edit: page 635 of the textbook called "Differential Equations" by Blanchard, Devany and Hall.
 
Last edited:
roam said:
I am wondering if I've even used the correct method for finding the number of steps?
It appears that you have. As mentioned before if you want to check this, you could confirm this using a program or a spreadsheet using Euler method with Δt = (0.2 / 7760) to see if it corresponds with your answer (for the spread sheet you would need to use 7761 rows, the initial state and 7760 steps).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
4
Views
4K
  • · Replies 65 ·
3
Replies
65
Views
7K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
Replies
2
Views
3K