How Many Students Are Not Involved in Any Afternoon Activities?

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Discussion Overview

The discussion revolves around a combinatorial problem involving students' participation in afternoon activities at a university. Participants are trying to determine how many students are not involved in any activities, as well as those participating exclusively in certain activities, using set theory concepts.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant calculates that 30 students do not participate in any activities, using union and intersection of sets.
  • Another participant suggests using a Venn diagram to visualize the problem, recommending starting from the intersection of all three activities.
  • A participant expresses curiosity about whether algebra of sets could also be used to solve the problem, indicating a preference for Venn diagrams for clarity.
  • One participant proposes that the answers to the remaining questions are 7 and 10, but another participant disagrees on the latter, suggesting a different interpretation of the students' participation.

Areas of Agreement / Disagreement

Participants generally agree on the solution to the first question but have differing views on the answers to the second and third questions, indicating unresolved disagreements regarding the calculations and interpretations of participation.

Contextual Notes

Participants have not fully resolved the assumptions regarding the distribution of students across the activities, and there are dependencies on how the intersections are defined and calculated.

Yankel
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Hello all,

I am struggling with this relatively simple task.

In a university with 88 students, each student can choose to participate in 3 afternoon activities: activity A, activity B and activity C. Each student can choose to participate in some activities, all or none.

33 students participate in activity A
28 students participate in activity B
33 students participate in activity C
14 students participate in activity A and B
18 students participate in activity A and C
10 students participate in activity B and C
6 students participate in activity A, B and C

1. How many students decided not to participate in any activity ?
2. How many students participate ONLY in activity A ?
3. How many students participate in activity A OR B, but NOT in C ?

I think I did "1" OK, I got that the answer is 30 (am I correct ?).

I solved it using union and intersection, and using the rule of union of 3 sets.

I find it hard to solve "2" and "3".
 
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You are correct for question 1. I find a Venn diagram is an invaluable tool for problems of this sort. Draw 3 intersecting circles to represent the 3 activities, and then work from the inside out, that is, start with the intersection of all 3, then fill in the 3 intersections of the pairs, and finally the 3 parts of each set with no intersection. You will then have all the information you need to easily answer the remaining 2 questions.

Can you proceed?
 
I think I understand what you mean by inside out, I think I can proceed, thank you !

Just for curiosity, isn't it also possible to be done using algebra of sets ?
 
Yankel said:
...
Just for curiosity, isn't it also possible to be done using algebra of sets ?

My inclination is that it is, but this is not an area in which I am very knowledgeable. I just find a Venn diagram to be very straightforward for a problem like this. :D
 
Ok, thanks :)

Just to verify, in "2" and "3", are the answers 7 and 10 ?
 
I agree with 7 for question 2, but for question 3 I have a different answer. I get 10 as the number of students participating only in activity B, but we need to include those that participate only in A AND in A and B (but not C).
 

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