How Many Students Are Not Involved in Any Afternoon Activities?

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SUMMARY

In a university with 88 students, the participation in three afternoon activities (A, B, and C) was analyzed. A total of 30 students do not participate in any activities, confirmed through the application of set theory principles. The number of students participating only in activity A is 7, while the number of students participating in activities A or B, but not C, is 10. The use of Venn diagrams is emphasized as an effective method for visualizing and solving such problems.

PREREQUISITES
  • Understanding of set theory concepts, including union and intersection
  • Familiarity with Venn diagrams for visual representation of sets
  • Basic algebra skills for manipulating set equations
  • Knowledge of combinatorial counting principles
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  • Study the principles of set theory, focusing on union and intersection operations
  • Practice creating and interpreting Venn diagrams for various set problems
  • Explore algebra of sets and its applications in problem-solving
  • Learn combinatorial counting techniques to enhance problem-solving skills
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This discussion is beneficial for mathematics students, educators, and anyone interested in combinatorial analysis and set theory applications in real-world scenarios.

Yankel
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Hello all,

I am struggling with this relatively simple task.

In a university with 88 students, each student can choose to participate in 3 afternoon activities: activity A, activity B and activity C. Each student can choose to participate in some activities, all or none.

33 students participate in activity A
28 students participate in activity B
33 students participate in activity C
14 students participate in activity A and B
18 students participate in activity A and C
10 students participate in activity B and C
6 students participate in activity A, B and C

1. How many students decided not to participate in any activity ?
2. How many students participate ONLY in activity A ?
3. How many students participate in activity A OR B, but NOT in C ?

I think I did "1" OK, I got that the answer is 30 (am I correct ?).

I solved it using union and intersection, and using the rule of union of 3 sets.

I find it hard to solve "2" and "3".
 
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You are correct for question 1. I find a Venn diagram is an invaluable tool for problems of this sort. Draw 3 intersecting circles to represent the 3 activities, and then work from the inside out, that is, start with the intersection of all 3, then fill in the 3 intersections of the pairs, and finally the 3 parts of each set with no intersection. You will then have all the information you need to easily answer the remaining 2 questions.

Can you proceed?
 
I think I understand what you mean by inside out, I think I can proceed, thank you !

Just for curiosity, isn't it also possible to be done using algebra of sets ?
 
Yankel said:
...
Just for curiosity, isn't it also possible to be done using algebra of sets ?

My inclination is that it is, but this is not an area in which I am very knowledgeable. I just find a Venn diagram to be very straightforward for a problem like this. :D
 
Ok, thanks :)

Just to verify, in "2" and "3", are the answers 7 and 10 ?
 
I agree with 7 for question 2, but for question 3 I have a different answer. I get 10 as the number of students participating only in activity B, but we need to include those that participate only in A AND in A and B (but not C).
 

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