How many ways can a four digit number be formed with different restrictions?

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Homework Help Overview

The discussion revolves around combinatorial problems, specifically focusing on arrangements and distributions of letters and digits. Participants explore various scenarios involving permutations and combinations, particularly in the context of forming four-digit numbers under specific restrictions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the arrangement of letters in words and the distribution of ice cream flavors among children. They also explore how to calculate permutations for four-digit numbers using different sets of digits, questioning the validity of their methods and assumptions.

Discussion Status

There is an active exchange of ideas, with participants offering corrections and alternative approaches to the problems presented. Some participants express uncertainty about their calculations and seek clarification on the application of permutations versus combinations. Multiple interpretations of the restrictions for forming four-digit numbers are being explored.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the use of certain digits or require specific conditions for the last digit of the number. There is ongoing discussion about whether digits can be repeated and how that affects the calculations.

  • #31
Erzeon said:
From the question you wrote, you can't repeat the same number,
ok, i get it...

but this one i don't get it...the last number should be odd because when it's odd, it produces an odd number
 
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  • #32
i mean last digit, odd numbers always have their last digit as an odd number.
 
  • #33
ohh, i know what you mean now... so the answer in 4d would be...still figuring out...lol
 
  • #34
is it 9!/5! or 9x8x7x6 for 4d? since the numbers runs from 0 to 9, but there is only 5 odd numbers, and same thing with 4e?
 

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