How Much Air Is Needed to Cool Water in a Copper Tube?

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Discussion Overview

The discussion revolves around determining the amount of air needed to cool water flowing through a copper tube, with specific parameters including initial and target temperatures of the water and a time constraint for cooling. The focus is on heat transfer and thermodynamics in a practical application.

Discussion Character

  • Technical explanation
  • Experimental/applied
  • Homework-related

Main Points Raised

  • One participant seeks to calculate the required airflow to cool water from 70°C to 35°C in under 2 minutes, knowing it will take approximately 250 W of power.
  • Another participant questions whether the water is flowing or stagnant, and requests details about the pipe's dimensions and ambient air temperature.
  • A suggestion is made that knowing the required power allows for calculating airflow by multiplying the desired airflow by the specific heat of air and the desired temperature change, with an additional safety factor.
  • The original poster clarifies that the water is flowing and can adjust its velocity to meet the requirement of dispensing 8oz in 2 minutes, providing dimensions of the pipe and the ambient air temperature range.

Areas of Agreement / Disagreement

Participants are gathering information and exploring different aspects of the problem, but no consensus has been reached on the specific calculations or methods to determine the required airflow.

Contextual Notes

Participants have not yet established the velocity of the water flow or the exact parameters for the calculations, which may affect the outcome. The discussion is dependent on specific definitions and assumptions regarding airflow and heat transfer.

Vig16
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I was asked to determine how much Air is needed to cool a copper tube. The air will be blowing on the outside surface of the tube as there will be water running through the tube.

The starting temperature of the water will be 70°C and the goal end temperature is 35°C...all done in less than 2 minutes. I already know that it will take ~250 W to do this; however, how would I determine the amount of air needed? Am I looking for the velocity of the air to cool it? If so, what equation should I use to solve for this?

I won't be able to have room temperature water available to cool the solution, neither will I be able to use ice. This needs to be repeated on command, so I'll need a fan that will kick on to cool the piping as the 70°C starts flowing through.

As you can see I'm quite rusty on my heat transfer and thermodynamics. It doesn't help that I can't find my textbook from when I was in school either!
 
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A few questions:
  • Is the water flowing through the pipe or is it being stagnantly held in place? If it's flowing, at what velocity?
  • What's the length and diameter of the pipe?
  • What temperature is the ambient air at?
 
If you know the required power you can simply multiply the desired airflow by the specific heat of air and desired delta-T... then add a safety factor.
 
Sorry about that. I'll answer your questions in order...

1. The water is flowing through the pipe, but the velocity is not determined yet. I can make it as fast or slow as I want so long as I can dispense 8oz of water in 2 minutes which is what I need to cool (sorry for leaving that important fact out).

2. The pipe is 3/8" diameter and right now it's in an aluminum box that's 5"x6"x1.5". I can have copper tubing leading into it as well though.

3. The ambient air is at 22-27 deg C

ddelaiarro said:
A few questions:
  • Is the water flowing through the pipe or is it being stagnantly held in place? If it's flowing, at what velocity?
  • What's the length and diameter of the pipe?
  • What temperature is the ambient air at?
 

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