How Much Cl2, C, and TiCl4 Are Produced from 1.25 mol TiO2?

[UNknown 2010]

Hi my question is
TiO2 + C + 2Cl = TiCl4 + CO2
If you have 1.25 mol TiO2. Answer this question:
1- The mas of Cl2
(1.25 mol TiO2) ((2 mol Cl2)/(1 mol Tio)) = 3 mol Cl2
(3 mol Cl2)((35.453 g Cl2)/(1 mol Cl2)) = 106.359 g Cl2

2- The mas of C
(1.25 mol TiO2) ((1 mol C)/(1 mol Tio)) = 1.25 mol C
(1.25 mol C)((12.011 g C)/(1 mol C)) = 15.01 g C

3- The mas of TiCl4
(1.25 mol TiO2) ((1 mol TiCl4)/(1 mol Tio)) = 1.25 mol TiCl4
(1.25 mol TiCl4 ) ((189.679 g TiCl4)/(1 mol TiCl4)) = 237.1 g TiCl4

 

[Bystander]

(1.25 mol TiO2) ((2 mol Cl2)/(1 mol Tio)) = 3 mol Cl2

Looks good except for this; "two x one and one quarter equals three?"