How Much Does the Water Level Rise with a Submerged Object?

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving buoyancy and water displacement. The original poster presents a scenario where a submerged object affects the water level in a tank, seeking to understand the relationship between the object's weight in air and its weight in water.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the calculation of water level rise based on the weight difference of the object in air and water. Questions arise regarding the correct interpretation of weight versus mass and the appropriate use of units in calculations.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's calculations and questioning the assumptions made about weight and mass. Some guidance is offered regarding the correct application of density and gravitational force in the context of the problem.

Contextual Notes

There is confusion regarding the terminology used in the problem, particularly the distinction between weight and mass, which may be impacting the calculations and interpretations presented by participants.

jayjay112
Messages
36
Reaction score
0
An object weighs 30kg in air it is lowered into a square tank (1m x 1m)
the weight of the object in the water is 16kg. how much does the water level in the tank raise?


Heres my attempt.
30-16 = 14kg

14kg = 14 m^3

1 x 1 x h = 14

h = 14 metres.

Is this correct it doesn't seem right for some reason??

Thank you for your time
 
Physics news on Phys.org
Way too much. What is water density?
 
Last edited by a moderator:
1000 kg/m^3 = rho

so W/1000 x 9.81 = h?

=14000/9810 = 1.43m?

Thanks for the help
 
Worst approach you can take it to calculate first, apply units later. That's what you are doing and your answer is all the time wrong.
 
Last edited by a moderator:
I don't understand? do you mean my formula is correct but my units are wrong?

14/98100= 1.43 x 10^-3?
 
What is what of what?

Numbers you present - as long as they don't have any units - don't make any sense.
 
Last edited by a moderator:
14kg / (1000kg/m^3 x 9.81m/s)= 1.43 x 10^-3 m
 
I guess the text of the problem creates some confusion. They call the 30 kg "weight" but it's the mass actually.
What is the weight of the water displaced? Not the mass.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
12K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
6K
Replies
8
Views
3K