How Much Electricity is Needed to Cool Molten Glass in Industrial Manufacturing?

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SUMMARY

The discussion focuses on calculating the electricity required to cool molten glass in industrial manufacturing. The manufacturer produces 97,000 tons of glass annually, with a melting point of 1673K and an ambient temperature of 293K. The specific heat capacity of glass is 0.837 kJ/kg.K, leading to a heat removal rate of 3,871 kW. The conversation also touches on the coefficient of performance (COP) in refrigeration systems, emphasizing that a heat exchanger may be a viable alternative for cooling without requiring work typical of refrigeration cycles.

PREREQUISITES
  • Understanding of thermodynamics, specifically heat transfer principles.
  • Knowledge of specific heat capacity and its application in cooling calculations.
  • Familiarity with the concept of the coefficient of performance (COP) in refrigeration systems.
  • Basic understanding of heat exchangers and their operational principles.
NEXT STEPS
  • Research the Carnot Cycle and its implications for refrigeration efficiency.
  • Learn about the design and operation of heat exchangers in industrial applications.
  • Explore advanced refrigeration techniques and their COP calculations.
  • Investigate energy consumption metrics for industrial cooling systems.
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Manufacturing engineers, thermal system designers, and energy efficiency specialists seeking to optimize cooling processes in glass production and similar industrial applications.

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Homework Statement



A glass manufacturer operates 11 months of the year and produces 97,000 tons of glass per year that needs to be cooled to ambient temperatures. The melting point of glass is 1673K and ambient temperature is assumed to be 293K. The specific heat capacity of glass is 0.837 kJ/kg.K. How much electricity is required to power a refrigeration system to remove the amount of heat given off by the molton glass?

Homework Equations



Qdot=MdotCpΔT

The Attempt at a Solution



Mdot = 97,000,000 kg / (335 days x 24 hours/day x 3600 seconds/hour) = 3.35 kg/s

Qdot = 3.35kg/s x 0.837 kJ/kg.K x (1673K-293K) = 3,871 kW

I know I have to do something with the COP but I'm completely stuck now. Any ideas guys?
 
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If you assume the coefficient of performance is at the upper limit (and is based on the reversed Carnot Cycle), then the COP is given by

COP = T_{L} / (T_{H} - T_{L})

where T_{L} is the temperature of the low temp reservoir, and T_{H} is the temperature of the high temp reservoir.
 
Sorry, that COP definition doesn't apply here. The only refrigeration I'm familiar with is used to move heat from a cold region to a hot region, relatively speaking of course. The reason work is used is because heat will not flow from cold to hot on it's own. Your situation is different, though. If you wanted to, you could cool the molten glass using a heat exchanger. But a heat exchanger doesn't require work in the sense that a refrigeration cycle does.
 

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