How Much Energy Does a Squash Ball Lose After Bouncing?

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Homework Help Overview

The discussion revolves around the energy loss of a squash ball after bouncing, specifically focusing on the percentage of gravitational potential energy lost when the ball falls from a height of 3.0 m and bounces back to a height of 0.076 m. The subject area includes concepts of gravitational potential energy and energy conservation principles.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial and final heights of the squash ball and how to calculate the energy loss using gravitational potential energy formulas. There is a question regarding the interpretation of the height of 0.076 m and whether it is a direct measurement or a fraction of the initial height.

Discussion Status

Some participants have provided guidance on comparing the gravitational potential energy values at the start and end positions. There is an ongoing clarification about the height measurement and how to approach the calculation of energy loss.

Contextual Notes

Participants note that the problem does not involve an "x" variable, which has contributed to confusion regarding the approach. The discussion also highlights the lack of examples provided by the teacher for similar problems.

Araiz
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Homework Statement


This is a simple question but I can't seem to solve it( I don't know if this is advanced physics or not first time on this website, it said Work and that is part of this energy loss problem) here is the problem: What percentage of its gravitational potential energy does a squash ball lose if it falls from 3.0 m and returns to a height of .076 after bouncing once?

Homework Equations


(100-x)(Ek1 + Eg1)/100 = Ek2 + Eg2
Ek = 1/2mv²
Eg = mgh

[/B]

The Attempt at a Solution


Honestly, my Teacher did not give any example on a question with no "x" variable like this one, so literally I had no clue on how to attempt this question.
 
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Araiz said:

Homework Statement


This is a simple question but I can't seem to solve it( I don't know if this is advanced physics or not first time on this website, it said Work and that is part of this energy loss problem) here is the problem: What percentage of its gravitational potential energy does a squash ball lose if it falls from 3.0 m and returns to a height of .076 after bouncing once?

Homework Equations


(100-x)(Ek1 + Eg1)/100 = Ek2 + Eg2
Ek = 1/2mv²
Eg = mgh

[/B]

The Attempt at a Solution


Honestly, my Teacher did not give any example on a question with no "x" variable like this one, so literally I had no clue on how to attempt this question.
Welcome to the PF.

You would just compare the E=mgh values of PE for the start and end positions of the ball. But what does "to a height of 0.076" mean? 0.076 meters, or 0.076*3.0 meters?
 
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berkeman said:
Welcome to the PF.

You would just compare the E=mgh values of PE for the start and end positions of the ball. But what does "to a height of 0.076" mean? 0.076 meters, or 0.076*3.0 meters?
Thanks !

Its H1= 3.0 m and H2= .076, I know that for sure because, the ball is first at 3.0 M then it bounces and reaches a height of .076m. that's all i got from the question, oh and g= 9.80.
 
Araiz said:
Thanks !

Its H1= 3.0 m and H2= .076, I know that for sure because, the ball is first at 3.0 M then it bounces and reaches a height of .076m. that's all i got from the question, oh and g= 9.80.
So all you have to do is calculate the two mgh values, and figure out what percentage of the original PE was lost in the bounce. :smile:
 
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