How much energy is required to ionize one atom of Al?

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SUMMARY

The first ionization energy of aluminum (Al) is 578 kJ/mol, which translates to approximately 9.5 x 10^-19 J for a single atom. To ionize one atom of Al, the energy required is derived from the molar energy divided by Avogadro's number. The balanced chemical equation for the first ionization of aluminum is Al(s) → Al⁺(g) + e⁻. The wavelength of a photon needed to ionize a single atom can be calculated using the equation E = H * C / λ, where H is Planck's constant (6.63 x 10^-34 Js) and C is the speed of light (3.0 x 10^8 m/s).

PREREQUISITES
  • Understanding of ionization energy and its units (kJ/mol)
  • Familiarity with Avogadro's number (6.022 x 10^23 atoms/mol)
  • Knowledge of Planck's constant (6.63 x 10^-34 Js)
  • Basic principles of photon energy and wavelength calculations
NEXT STEPS
  • Calculate the energy required to ionize a single atom of aluminum using Avogadro's number
  • Learn how to derive the wavelength of a photon from its energy using E = H * C / λ
  • Explore the concept of moles in relation to photons and ionization processes
  • Study the implications of ionization energy in chemical reactions and material properties
USEFUL FOR

Chemistry students, educators, and anyone preparing for exams related to atomic structure and ionization processes.

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a. the first ionization energy of aluminum is 578 kJ/mol. How much energy is required to ionize one atom of Al?
I put E= 578 kJ/mol . is this how to start?

b. Write out balanced chemical equation that represents the first ionization of aluminum (you must include the physical states)

c. Calculate the wavelength of a photon that has just enough energy to ionize a single atom of aluminum.

d. how many moles of photons with the wavelength you calculated in part c are required to ionize 1.15 moles of aluminum?

Can you help me set these up. I am studying for a test and we have not been over all of these yet? Thanks.
 
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jewilki1 said:
a. the first ionization energy of aluminum is 578 kJ/mol. How much energy is required to ionize one atom of Al?
I put E= 578 kJ/mol . is this how to start?
the energy given is in terms of moles. You are trying to find the energy for a single atom. So how many atoms in a mole...

jewilki1 said:
b. Write out balanced chemical equation that represents the first ionization of aluminum (you must include the physical states)
Remember, Aluminum like to ionize to +3.

jewilki1 said:
c. Calculate the wavelength of a photon that has just enough energy to ionize a single atom of aluminum.
Using the equation E = H * C / Lambda,
where E is the energy of a wave, H is planks constant, C is the speed of light in a vacuum, and Lamba is the wavelength of the wave, you can solve for the wavelength since you know Energy and H and C are constants.
H = 6.63 E-34 Js/photon
C =3.0 E8 m/s

jewilki1 said:
d. how many moles of photons with the wavelength you calculated in part c are required to ionize 1.15 moles of aluminum?
I think 1 photon will ionize 1 atom assuming the photon is of the correct energy.
 

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