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Calculate the Second Ionization Energy of Lithium

  1. Oct 18, 2012 #1
    1. The problem statement, all variables and given/known data

    [​IMG]
    Given
    -Total Energy for [itex]Li \rightarrow Li ^{3+} = 1.960 * 10^{4} kJ/mol[/itex]

    -First Ionization Energy of Li = [itex]5.20 * 10^{2} kJ/mol[/itex]

    2. Relevant equations
    Other than the equation in the image, I used the equation:
    Etotal = E1 + E2 + E3

    3. The attempt at a solution
    Since Etotal and E1 are given, I have E2 and E3 left to solve.

    To solve for E3, I used the equation in the picture.

    Li^2+= A hydrogen atom (1 electron), I used the equation in the picture to solve for the energy for a single electron. Energy = -1.962*10^-17 J

    The problem is, I don't know what to do with that number. How do I convert energy of a single electron to ionization energy?
     
  2. jcsd
  3. Oct 18, 2012 #2

    AGNuke

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    Gold Member

    That energy is the energy you need to supply to the electron in order to overcome coulombic forces, i.e. to ionize the species. Simple enough.
     
  4. Oct 18, 2012 #3

    Borek

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    Staff: Mentor

    What is a mole?
     
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