How Much Energy is Stored in a Hurricane's Rotation?

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SUMMARY

The energy stored in the rotational motion of a hurricane can be estimated using the formula for kinetic energy (KE = (1/2) * I * w^2), where I is the moment of inertia and w is the angular velocity. In this case, the hurricane is modeled as a uniform cylinder with a diameter of 300 km and a height of 5 km, with air density at 1.3 kg/m³. The outer edge of the hurricane moves at a speed of 200 km/h, leading to a calculated energy of approximately 4E17 J. Key considerations include using the correct mass derived from the cylinder's volume and incorporating the height in calculations.

PREREQUISITES
  • Understanding of kinetic energy and its formula
  • Knowledge of moment of inertia for a cylinder
  • Ability to convert between linear and angular velocity
  • Familiarity with basic geometry of cylinders
NEXT STEPS
  • Calculate the mass of a cylinder using the formula: mass = density × volume
  • Learn how to derive angular velocity from linear velocity using the formula v = wR
  • Explore the implications of height in volume calculations for three-dimensional shapes
  • Investigate the effects of different densities on energy calculations in fluid dynamics
USEFUL FOR

Students studying physics, particularly those focusing on rotational motion and energy calculations, as well as educators looking for practical examples of applying kinetic energy formulas in real-world scenarios.

sinclair18
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Rotational Motion Question -- please help

Homework Statement



Estimate the energy stored in the rotational motion of a hurricane. Model the hurricane as a uniform cylinder 300 km and 5 km high, made of air whose mass is 1.3 kg/m^3. Estimate the outer edge of the hurricane to move at a speed of 200 km/h.



Homework Equations



KE = (1/2)*I*w^2

v= wR

For a uniform cylinder, I=(1/2)MR^2 (but it's hollow so would that make a difference, even though you're only given one radius)

The Attempt at a Solution


So here's how I started out:

KE = (1/2)*I*w^2

v= wR

--> Therefore KE = (1/2)[(1/2)MR^2][v/R]^2

The answer is 4E17 J, but I can't seem to get that. Can someone please tell me where I'm going wrong? I've been doing this problem for so long and I'm just not getting what I keep doing wrong. I feel like it might have something to do with the mass I'm using (M=1.3 kg/m^3) or the fact that I'm neglecting the height (h=5km)? It's not supposed to be a difficult problem...please help!
 
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sinclair18 said:

Homework Statement



Estimate the energy stored in the rotational motion of a hurricane. Model the hurricane as a uniform cylinder 300 km and 5 km high, made of air whose mass is 1.3 kg/m^3. Estimate the outer edge of the hurricane to move at a speed of 200 km/h.

Homework Equations



KE = (1/2)*I*w^2

v= wR

For a uniform cylinder, I=(1/2)MR^2 (but it's hollow so would that make a difference, even though you're only given one radius)

The Attempt at a Solution


So here's how I started out:

KE = (1/2)*I*w^2

v= wR

--> Therefore KE = (1/2)[(1/2)MR^2][v/R]^2

The answer is 4E17 J, but I can't seem to get that. Can someone please tell me where I'm going wrong? I've been doing this problem for so long and I'm just not getting what I keep doing wrong. I feel like it might have something to do with the mass I'm using (M=1.3 kg/m^3) or the fact that I'm neglecting the height (h=5km)? It's not supposed to be a difficult problem...please help!

What you're given is not a "mass" of air - it's the density of air. Units are mass per unit volume.

What's the volume of a cylinder? Hence, what is its mass? Work in symbols throughout (try to use LaTex, if possible), as there's less chance of error.

You definitely need the height that's given. Also, I'm assuming that 300km is the diameter, not the radius?
 
Yeah I just figured it out actually thanks soooo much!
 
sinclair18 said:
Yeah I just figured it out actually thanks soooo much!

No problem. Glad to help (if I did).
 

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