How Much Force Is Needed for One Million Atmospheres with Diamond Tip Presses?

  • Thread starter Thread starter JWHooper
  • Start date Start date
  • Tags Tags
    Diamond Physics
Click For Summary

Homework Help Overview

The discussion revolves around calculating the force required to achieve a pressure of one million atmospheres using diamond tip presses with a specified diameter. The subject area includes concepts of pressure, force, and area in physics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between pressure, force, and area using the equation P = F/A. There are attempts to convert units and calculate the necessary force based on the given pressure and area. Questions arise regarding the appropriateness of using pounds versus Newtons for force measurement.

Discussion Status

Some participants express confidence in the calculations presented, while others suggest considering unit conversions more carefully. The discussion reflects a mix of interpretations regarding the preferred units of measurement and their implications for understanding the problem.

Contextual Notes

There is mention of the potential confusion arising from using different systems of measurement, particularly with the diameter given in millimeters and the force expressed in pounds. This raises questions about the expectations for unit consistency in the problem.

JWHooper

Homework Statement


Diamond tip presses are now capable of creating pressures in excess of one million atmospheres. Suppose the tips of the presses were circles with an diameter of one millimeter. How much force must be applied to the tips to create a pressure of one million atmospheres?


Homework Equations


P = F/A, where P is the pressure, F is the force and A is the area.
r is the radius in my solution.


The Attempt at a Solution


P = 10^6 atm, r = 1.97 x 10^-2 in
P = (10^6)(14.7 lb/in^2) = 1.47 x 10^7 lb/in^2 (unit conversion)
A = (pi)(1.97 x 10^(-2))^2 = 1.22 x 10^(-3) in^2

F = PA = (1.47 x 10^7 lb/in^2)(1.22 x 10^(-3) in^2) = 1.79 x 10^4 lb
Did I do anything wrong? I just want to make sure.

J.
 
Physics news on Phys.org
JWHooper said:

Homework Statement


Diamond tip presses are now capable of creating pressures in excess of one million atmospheres. Suppose the tips of the presses were circles with an diameter of one millimeter. How much force must be applied to the tips to create a pressure of one million atmospheres?


Homework Equations


P = F/A, where P is the pressure, F is the force and A is the area.
r is the radius in my solution.


The Attempt at a Solution


P = 10^6 atm, r = 1.97 x 10^-2 in
P = (10^6)(14.7 lb/in^2) = 1.47 x 10^7 lb/in^2 (unit conversion)
A = (pi)(1.97 x 10^(-2))^2 = 1.22 x 10^(-3) in^2

F = PA = (1.47 x 10^7 lb/in^2)(1.22 x 10^(-3) in^2) = 1.79 x 10^4 lb
Did I do anything wrong? I just want to make sure.

J.
Looks good. But you might want to convert the force to Newtons since the diameter was given in millimeters (personally, I like it in pounds).
 
PhanthomJay said:
Looks good. But you might want to convert the force to Newtons since the diameter was given in millimeters (personally, I like it in pounds).
So, it doesn't really matter if pounds is used or Newtons is used?
 
JWHooper said:
So, it doesn't really matter if pounds is used or Newtons is used?
The USA, Myanmar, and Liberia use pounds as the standard unit of force. Everywhere else in the world, the Newton (SI system) is the standard unit of force. Since the problem noted the diameter in mm, it may be looking for Newtons of force, not pounds, because it's bad enough working with 2 systems, let alone mixing the two. Being from the States, I like pounds, because I get a good 'feel' for how much 18000 pounds is. When you convert pounds to Newtons, 18000 pounds is about 80000 Newtons. I wouldn't have a good feel for how much 80000N is without first converting it to pounds. If this is a Physics problem where you are asked to use SI, use Newtons.
 

Similar threads

Replies
6
Views
3K
  • · Replies 23 ·
Replies
23
Views
6K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
7
Views
7K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
22
Views
3K