1. The problem statement, all variables and given/known data How much charge would the Earth and Sun need to knock the Earth out of orbit. Then, assuming the distance from one proton to another and the length of one electron to another is 197 pm, find out how large of a block you would need of protium located on Earth and how large of a block of pure electrons located on the Sun you would need to accomplish the aforementioned result. Ignore the fact that a block of protium cannot exist since all of the protons would be repulsed by each other. Same for electrons. I made up this question. 2. Relevant equations F = gMm F = kqq 3. The attempt at a solution For the force of gravity the Earth's orbit around the Sun creates I have 6.7*10^-11 * 1.99 * 10^30 * 5.97 * 10^24 = 7.96 * 10^44 Nm^2 So to find out how much charge you need: 7.96 * 10^44 = kqq = kq^2 = (8.99 * 10^9)q^2 = 2.98 * 10^17 To find out how many protons you would need you divide 2.98 * 10^17 by the charge of one proton, which is 1.61 * 10^-19 which equals 1.85 * 10^36 protons. I think 197 pm is 1.97 * 10^-10 First I multiply them 1.97 * 10^-10 * 1.85 * 10^36 = 3.64 * 10^26 but then to get it in three dimensions I'm pretty sure you need to take the cube root. (3.64 * 10^26)^1/3 = 7.14 * 10^8 m^3 = 7.14 * 10^5 m^3 On the one hand the volume of the Earth is 1.08 * 10^12 km^3. So the block would be something 6 * 10^-5 % of the Earth's volume which is small. But on the other hand the block would be bigger than the United States which is large. Let me know if you see any mistakes in my calculations.