How Much K2SO4 Solution is Needed for a Specific Potassium Ion Concentration?

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SUMMARY

To prepare 450.0 mL of a 145 ppm potassium ion (K+) solution, the density of the solution is 1.01 g/mL, and the concentration of K2SO4 is 0.728 M. The required volume of K2SO4 solution can be calculated using the formula: volume = (mass of K+ needed) / (concentration of K2SO4 in mol/L). This involves converting ppm to grams and then to moles to find the necessary volume of the K2SO4 solution.

PREREQUISITES
  • Understanding of ppm (parts per million) calculations
  • Knowledge of molarity and molar mass
  • Familiarity with density and its application in solution preparation
  • Basic principles of mass conservation in chemistry
NEXT STEPS
  • Calculate the mass of K+ needed for a 145 ppm solution
  • Convert the mass of K+ to moles using the molar mass of K
  • Determine the volume of K2SO4 solution required using the concentration
  • Explore the relationship between concentration, volume, and mass in solution chemistry
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Chemistry students, laboratory technicians, and anyone involved in solution preparation and concentration calculations.

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Homework Statement


Want to prepare 450.0 mL of a 145 ppm K + ion solution. density of solution is 1.01 g/mL. solution is .728 M in K2SO4. How many mL of the K2SO4 solution need to use?


Homework Equations





The Attempt at a Solution



(.728 mol/L K2SO4 )(1.01g/mL)(450.0 mL)

i don't know what to do next...help?
 
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This is a simple mass conservation.

How much potassium will be present in the final solution?

What volume of the starting solution contains this amount of potassium?
 
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