How Much Money Would You Have After 30 Days of Doubling?

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Discussion Overview

The discussion revolves around a mathematical problem involving the calculation of total money given over 30 days, where the amount doubles each day starting from $1. Participants explore the implications of this doubling process and attempt to derive the total amount mathematically.

Discussion Character

  • Mathematical reasoning, Technical explanation, Debate/contested

Main Points Raised

  • One participant presents the problem of calculating the total amount given after 30 days of doubling starting from $1.
  • Another participant suggests a formula involving a summation, but does not provide the result.
  • A third participant corrects the previous claim about the formula, stating that the correct expression for the total amount is a geometric sum, specifically \(\sum_{n=1}^{30} 2^{n-1}\).
  • This participant provides the formula for the geometric sum and calculates the total as \(2^{30} - 1 = 1073741823\).
  • Another participant initially misinterprets the question and suggests using factorial notation, later retracting their statement upon realizing the misunderstanding.
  • A later reply asks for the final answer in dollar terms, indicating a desire for clarification on the total amount calculated.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the final answer, and there is some confusion regarding the correct mathematical approach to the problem.

Contextual Notes

Some participants express uncertainty about the calculations and interpretations of the problem, indicating potential misunderstandings of the original question.

jtesttubes
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I have been asked this question before 6 months, it was an interesting question.

Here is the question i just want to share.
Today let me simplify it as 1st day i give 1 $ 2nd Day i double it to 2$ I am going to give you like this for 30 days how much money i would have totally given at the end of 30 days... this is the question initially i thought simple and i found there is really a calculation behind it. I leave it to the members to find out the answer.
 
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Sum((n-1)^2,n=1,30)

Don't know what the number is.
 
No, "doubling" would be 2^{n-1}, not (n-1)^2.

And the sum: \sum_{n=1}^{30} 2^{n-1} is a geometric sum. A geometric sum is of the form \sum_{n=0}^N ar^{n-1}. It is well known that it totals
a\frac{1- r^{N}}{1- r}
For a= 1, r= 2, that is
\sum_{n=0}^N= \frac{1- 2^N}{1- 2}= 2^{N}- 1
For n= 30, that is 230-1= 1073741823.
 
Last edited by a moderator:
THanks Halls of Ivory. I switched the base and exponent.
 
Couldn't you just do

30!=2.6525286\cdot10^{32}

Edit: Never mind, I read the original question wrong.
 
Ok david you have worked it out well, what is the answer in $
 

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