How much power is needed to haul a weight up an incline at a certain speed

Click For Summary
SUMMARY

The discussion centers on calculating the power required to pull a 250 lb load up a 45-degree incline at a speed of 5 mph. The primary force to overcome is gravity, calculated using the formula m(g sin theta), resulting in approximately 175 pounds of force. Participants emphasize the importance of understanding the power calculation process and suggest that users should demonstrate their attempts before receiving further assistance. The conversation highlights the significance of considering additional factors such as air resistance and friction in real-world applications.

PREREQUISITES
  • Understanding of basic physics concepts, specifically forces and inclines.
  • Familiarity with the formula for gravitational force on an incline.
  • Knowledge of power calculation in mechanical systems.
  • Basic understanding of motor specifications and applications.
NEXT STEPS
  • Research the formula for calculating power: P = F × v, where F is force and v is velocity.
  • Explore the effects of air resistance and friction on power requirements in inclined planes.
  • Investigate motor specifications suitable for hauling loads on inclines, focusing on torque and power ratings.
  • Learn about different types of motors and their applications in moving heavy loads.
USEFUL FOR

Students working on physics projects, engineers designing mechanical systems, and anyone interested in understanding the dynamics of moving loads on inclines.

gmatt244
Messages
1
Reaction score
0
TL;DR
Power needed to pull weight up an incline
Good afternoon everyone, I need help with a certain calculation. How much power is needed to pull a 250lb load up a 45 degree incline at 5 mph. I am working on a project at school and would like to know what kind of motor we can use. Thank you very much!
 
Engineering news on Phys.org
You have to overcome gravity and air resistance and rolling friction and axle friction.
Ignoring the last three for now, and just looking at gravity, it produces a force down the incline of
m(g sin theta) = (250/32)(32)(.707) or about 175 pounds. But before we talk about power, we need to know if doing the power calculation yourself is part of your assignment, because we don’t give homework help without your first showing an attempt. I already gave you a hint.
 
  • Like
Likes   Reactions: anorlunda

Similar threads

Replies
9
Views
2K
Replies
7
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
34
Views
5K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
7
Views
2K
  • · Replies 120 ·
5
Replies
120
Views
25K