The discussion centers on calculating the amount of water that boils off when a 0.7 kg iron horseshoe at 1200°C is dropped into 0.5 L of water at 30°C. The key equations used include Q = mcΔT for both the horseshoe and the water, where m is mass, c is specific heat, and ΔT is the change in temperature. The final calculations reveal that approximately 0.0922 kg (or 0.0922 L) of water boils off, based on the heat exchange until thermal equilibrium is reached.
PREREQUISITESStudents in physics or engineering, particularly those studying thermodynamics, as well as professionals involved in heat transfer calculations and thermal system design.
haruspex said:Right, so how much water will boil off.
Looks right.Shmiam said:with delta(E) = 0 = Qshoe + Qsteam
-Qshoe = Qsteam
208076.96J = L Msteam with L being the latent heat of vaporization = 2256 kJ/kg = 2256000 J/kg
Msteam = .0922kg = .0922L
Awesome! Thank you very much for all of the guidance, I think it helped me to understand the concepts here much moreharuspex said:Looks right.
That's a good result then.Shmiam said:Awesome! Thank you very much for all of the guidance, I think it helped me to understand the concepts here much more