Find the mass of water that vaporizes when 3.02 kg of mercury at 223 °C is added to 0.347 kg of water at 83.4 °C.
Mercury Q = Water Q + Water mL
mc∆t= mc∆t + mL
The Attempt at a Solution
mass of vapor = ((3.02)(140)(223-tfinal) - (4186)(.347)(change in temperature))/100
I don't know the change in temperatures for sure, all the ones i have tried are wrong.