How Much Work Is Done by Force Acting Along the X-Axis?

[Ink]

Hi everyone

I have a question

A force acting on an object moving along the x-axis is given by Fx=(10x-2.0x^2)N
Where x is in m. how much work is done by this force as the object moves from x=-1 to x=+6

My answer was:
when it says the object moves from -1 ro +6, that means it looks like triangle and the height will be 6m

I used this formula to getthe area of triabgle
Wab = 1/2 (base) (high), where the high is 6, but what is the base?

Here I am lost

 

[LowlyPion]

Hi everyone

I have a question

A force acting on an object moving along the x-axis is given by Fx=(10x-2.0x^2)N
Where x is in m. how much work is done by this force as the object moves from x=-1 to x=+6

My answer was:
when it says the object moves from -1 ro +6, that means it looks like triangle and the height will be 6m

I used this formula to getthe area of triabgle
Wab = 1/2 (base) (high), where the high is 6, but what is the base?

Here I am lost

What they are wanting is the integral of the function over the range -1 to +6

Fx = 2*x -10*x²