How much work is done to move 1.7 microCoulombs ?

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SUMMARY

The discussion centers on calculating the work done to move 1.7 microCoulombs of charge across a 1.5 V battery. The correct formula for work (W) is W = Q * V, where Q is the charge in Coulombs and V is the voltage. Participants emphasize the need to convert microCoulombs to Coulombs, leading to the calculation of work as W = 1.7 x 10^-6 C * 1.5 V, resulting in 2.55 x 10^-6 Joules. Understanding the definition of voltage as the energy per unit charge is crucial for solving this problem.

PREREQUISITES
  • Understanding of electrical potential and voltage
  • Knowledge of charge units (Coulombs and microCoulombs)
  • Basic principles of work and energy in physics
  • Familiarity with the formula W = Q * V
NEXT STEPS
  • Learn about the relationship between voltage, charge, and energy in electrical circuits
  • Study the concept of electrical potential energy
  • Explore the conversion between microCoulombs and Coulombs
  • Investigate practical applications of work done in electrical systems
USEFUL FOR

Students studying physics, particularly those focusing on electricity and magnetism, as well as educators seeking to clarify concepts related to electrical work and potential.

csimon1
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Homework Statement



How much work is done to move 1.7 microCoulombs of charge from the negative terminal to the positive terminal of a 1.5 V battery?

Homework Equations


I thought you multiply them together since P=IE? But this is wrong? What is the formula I use even? I know I need to convert microCoulombs to Coulombs.


The Attempt at a Solution

 
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You might try looking up the definition of electrical potential (i.e. "voltage").
 
I still don't understand?? Can you explain further. This is a five part problem and this is the only part I'm stuck on
 
Voltage is DEFINED as the potential difference that one joule of energy can move one coloumb of charge across.
 

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