MHB How Much Work is Required to Stretch a Spring 3 Meters from Equilibrium?

Click For Summary
To determine the work required to stretch a spring 3 meters from its equilibrium position, Hooke's Law (F = kx) is applied to find the spring constant k using the provided data of 50 N force at 5 m. The work done can then be calculated using the formula W = (1/2)kx^2. Additionally, the discussion includes evaluating the improper integral $\int_{0}^{\infty} \frac{dx}{x^2-16}$, suggesting the use of partial fraction decomposition for simplification. A hint is provided to factor out -1 from the denominator for easier integration, particularly if one is familiar with the derivatives of inverse hyperbolic functions. Understanding these concepts is crucial for successfully solving similar problems on the final exam.
ineedhelpnow
Messages
649
Reaction score
0
my final is tomorrow and my instructor gave a list of questions that will be similar to the ones on the final exam and i want to see how they should be done properly. I've been working on other problems but i can't get past these ones. thanks
a spring on a horizontal surface can be stretched 5m from equilibrium position with force 50 N. how much work is done stretching the spring 3m from the equilibrium position?evaluate the integral
$\int_{0}^{\infty} \ \frac{dx}{x^2-16}$
 
Last edited:
Physics news on Phys.org
ineedhelpnow said:
a spring on a horizontal surface can be stretched 5m from equilibrium position with force 50 N. how much work is done stretching the spring 3m from the equilibrium position?
Hooke's Law says F = kx (using magnitudes). So you can use the initial information to find k. Then W = (1/2)kx^2.

ineedhelpnow said:
evaluate the integral
$\int_{0}^{\infty} \ \frac{dx}{x^2-16}$

Hint: Use a partial fraction decomposition:
\frac{1}{x^2 - 16} = \frac{A}{x + 4} + \frac{B}{x - 4}.

-Dan
 
For the improper integral, you can also factor -1 out of the denominator which will turn it into a very familiar antiderivative :)

EDIT: It's only familiar if you know the derivatives of inverse hyperbolic functions.
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
2
Views
7K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 13 ·
Replies
13
Views
5K