MHB How much would Mrs. Baker pay for 8 pounds of bananas?

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Mrs. Baker paid $2.50 for 5 pounds of bananas, establishing a cost of $0.50 per pound. The equation relating cost (c) to pounds (p) of bananas is C(p) = 0.50p. To find the cost for 8 pounds, the calculation shows C(8) = 0.50 * 8 = $4. This confirms that Mrs. Baker would pay $4 for 8 pounds of bananas. The discussion effectively demonstrates the relationship between cost and weight in a straightforward manner.
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Mrs. Baker paid 2.50 for 5 pounds of bananas. Write an equation relating the cost c to the number of pounds p of bananas.How much would Mrs. Baker pay for 8 pounds of bananas?

My Work:

2.50/c = 5/8

5c = 2.50 • 8

5c = 20

c = 4 dollars

Equation:

The cost per pound is 2.50 ÷ 5 = 0.50.

C(p) = 0.50p
 
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Looks good.
 
This is so cool. I am interested in the set up.
 
You answered the second question, "How much would Mrs. Baker pay for 8 pounds of bananas?" but did not do the first, "Write an equation relating the cost c to the number of pounds p of bananas."
 
HallsofIvy said:
You answered the second question, "How much would Mrs. Baker pay for 8 pounds of bananas?" but did not do the first, "Write an equation relating the cost c to the number of pounds p of bananas."

Actually, RTCNTC did, just in reverse order.

RTCNTC said:
Equation:

The cost per pound is 2.50 ÷ 5 = 0.50.

C(p) = 0.50p

We can actually now fill in the cost for 8 pounds of bananas:
$$C(8\text{ pounds}) = 0.50\frac{\text{£}}{\text{pound}} \cdot 8\text{ pounds} = 4\text{ £}$$
which agrees with the result RTCNTC found earlier.
 
Thank you everyone.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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