How Often Will Two Children Swinging at Different Rates Sync Up in a Minute?

  • Thread starter Thread starter aknita
  • Start date Start date
  • Tags Tags
    Children
Click For Summary
SUMMARY

Two children swinging at different rates will sync up multiple times within a minute. One child completes 20 cycles per minute, while the other completes 26 cycles per minute. The calculation shows that they will swing together an additional 6 times during that minute. The method used involved calculating the frequency of each swing and determining the difference to find the number of sync points.

PREREQUISITES
  • Understanding of basic frequency calculations
  • Knowledge of cycles per minute
  • Familiarity with mathematical problem-solving techniques
  • Ability to interpret and analyze periodic functions
NEXT STEPS
  • Study the concept of frequency in oscillatory motion
  • Learn about least common multiples (LCM) in periodic functions
  • Explore mathematical modeling of periodic phenomena
  • Investigate real-world applications of synchronization in physics
USEFUL FOR

Students in physics, educators teaching oscillatory motion, and anyone interested in mathematical problem-solving related to periodic functions.

aknita
Messages
1
Reaction score
0
1. Two children are swinging on swings side by side. One completes 20 cycles in 1.0 min while the other completes 26 cycles in 1.0 min. If they start out together, how many additional times will they be swinging together during that minute? Explain.
2. The attempt at a solution
f=N/t
f1=20/60
=.333
f2=26/60
=.433

B.F=f2-f1
=.433-.333
=.1

.1=N/60

N=6 timesthe answer is correct, but i was wondering whether the way i calculated it was the proper method.
thanks in advance.
 
Physics news on Phys.org
Hi aknita,
welcome to PF. Hope we can be of help to you.

The question do not indicate along which lines the problem should be solved. But if it were an exam question the explanation might count more than half of the marks. Personally I would rather use the periods to do the calculation.

So, how did you came to the answer? Can you justify your approach?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
10K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
3
Views
16K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
Replies
9
Views
21K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 87 ·
3
Replies
87
Views
11K