(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A block of mass m_{1}= 2.0 kg is stacked on top of a block of mass m_{2}= 3.0 kg which is resting on top of a table

Both blocks and the table are made of the same material; so the coefficients of friction between all surfaces are the same

They are (attempt at a mew)m_{s}= .60 andm_{k}= .40.

A constant forceFis applied horizontally to m_{2}. WhenFis small, the two blocks move together with the same acceleration. At some point asFis increased, the top block will no longer move with m_{2}.

a. What is the minimum force F_{min}that is needed to start the two blocks moving?

b. What is the maximum force F_{max}that allows the two blocks to move together?

2. Relevant equations

F=ma

F_{s}=m_{s}n

F_{k}=m_{k}n

3. The attempt at a solution

For a, I just added the two masses together and multiplied by g to get a total N then multiplied that by the coefficient of static friction to get the force required to get the two blocks moving. I hope that is right.

For b, I am having a difficult time imagining what m_{1}(mass on top) is doing when the horizontal force applied to m_{2}(mass on bottom) gets larger. I'm assuming this problem requires the use of F=ma. I'm having trouble picturing all the forces in motion here as the horizontal force on m_{2}increases, particularly what is happening to the mass on top.

Any help would be much appreciated! Please and thank you!

Sorry I didn't make a picture for this. I'm on a computer where paint isn't even an option. >__<;;

**Physics Forums - The Fusion of Science and Community**

# Applied Force ,Kinetic Friction, Static Friction involving two stacked masses

Have something to add?

- Similar discussions for: Applied Force ,Kinetic Friction, Static Friction involving two stacked masses

Loading...

**Physics Forums - The Fusion of Science and Community**