How to approach this question using SUVAT equations?

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving two cars, X and Y, where car X travels at a constant speed and car Y starts behind it, traveling at a slower speed. Participants are attempting to apply SUVAT equations to relate their displacements and speeds over time.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the assignment of variables for the displacements of the cars and attempting to relate their equations. Some express confusion about how to connect distance with time based on provided graphs, while others suggest using specific values to visualize the problem.

Discussion Status

There are multiple interpretations of the problem setup, with participants exploring different assignments of variables and equations. Some guidance has been offered regarding the potential for a non-equation-based approach, and a few participants have acknowledged the need to consider initial conditions more carefully.

Contextual Notes

Participants note that the problem statement is incomplete as presented, highlighting the importance of including all relevant details for clarity. There is also mention of a specific distance between the cars at the start, which may influence the calculations.

Physical_Fire
Messages
54
Reaction score
11
Homework Statement
A car X is travelling at a constant speed u along a straight road. At time t = 0 a second car Y is a
distance d0 behind car X and travelling at a speed v in the same direction. Speed v is less than
speed u
Relevant Equations
S= ut+(1/2) at^2
Hello,
I came across the question attached. To approach this, I assigned S1 to car Y and S2 to car X. So the displacement of Car Y is S1=S2 + d(naught). Then using S1= ut+(1/2) at^2 for car Y and S2= uT , I got to uT + d(naught) = VT + (1/2)aT^2. However, I am stuck here as I can't relate distance with time as per the graphs. Any nudge in the right direction is appreciated.

Thanks.
 

Attachments

  • 1728307384913.png
    1728307384913.png
    36.8 KB · Views: 82
Last edited:
Physics news on Phys.org
The question asks for the distance between cars X and Y. That's ##S_1 - S_2##
 
So i get s1-s2=UT-VT-(1/2)aT^2. I still cant see the relation
 
Physical_Fire said:
To approach this, I assigned S1 to car X and S2 to car Y. So the displacement of Car X is S1=S2 + d(naught). Then using S1= ut+(1/2) at^2 for car X and S2= uT , I got to uT + d(naught) = VT + (1/2)aT^2. However, I am stuck here as I can't relate distance with time as per the graphs. Any nudge in the right direction is appreciated.
It may be worth noting that the question can be solved without any equations - just using some careful thinking. (Perhaps you've already done that.) That's probably the approach intended by the question's author.

Of course, solving it using suvat equations is perfectly viable and is a valuable learning-experience.
 
  • Like
Likes   Reactions: MatinSAR and PeroK
Physical_Fire said:
So i get s1-s2=UT-VT-(1/2)aT^2. I still cant see the relation
Choose some possible values for ##u, v## and ##a## and draw a graph of that function.
 
  • Like
Likes   Reactions: Steve4Physics
I get this but this doesnt correspond to any of the given graphs.
 

Attachments

  • 1728311612381.png
    1728311612381.png
    18.1 KB · Views: 58
Physical_Fire said:
I get this but this doesnt correspond to any of the given graphs.
You forgot the ##d_0##. That graph shows cars X and Y being at the same place at ##t = 0##.
 
  • Like
Likes   Reactions: MatinSAR
Yep thanks, i got it now
 
Physical_Fire said:
Homework Statement: A car X is travelling at a constant speed u along a straight road. At time t = 0 a second car Y is a
distance d0 behind car X and travelling at a speed v in the same direction. Speed v is less than
speed u
Relevant Equations: S= ut+(1/2) at^2

Hello,
I came across the question attached. To approach this, I assigned S1 to car Y and S2 to car X. So the displacement of Car Y is S1=S2 + d(naught). Then using S1= ut+(1/2) at^2 for car Y and S2= uT , I got to uT + d(naught) = VT + (1/2)aT^2. However, I am stuck here as I can't relate distance with time as per the graphs. Any nudge in the right direction is appreciated.

Thanks.
You failed to completely state the problem. Yes, it's in the attachment, but you really should include a complete statement in the "Homework Statement"
 
  • Like
Likes   Reactions: MatinSAR

Similar threads

Replies
18
Views
2K
Replies
9
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 3 ·
Replies
3
Views
922
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 11 ·
Replies
11
Views
7K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K