- #1
DragonPetter
- 830
- 1
This is not homework, but is not general discussion, so not sure where this would go.
In class we were deriving with the radial equations of a hydrogen atom, and in one of the equations was the commutator term:
[tex]\left[ \frac{d}{d\rho}, \frac{1}{\rho}\right][/tex]
my attempt was:
[tex]\left[ \frac{d}{d\rho}, \frac{1}{\rho}\right][/tex]
=
[tex]\left(\frac{d}{d\rho} \cdot \frac{1}{\rho}\right) - - \left(\frac{1}{\rho} \cdot \frac{d}{d\rho}\right) = 2\left(\frac{d}{d\rho}\frac{1}{\rho}\right) = \frac{-2}{\rho^{2}}[/tex]
I know above is incorrect, but how is this commutator calculated? For some reason when I try, I get the wrong result, but I'm confused on exactly how to do it.
Also, I am confused on how to accept that the complex conjugate of [tex]\frac{d}{d\rho} = \frac{-d}{d\rho}[/tex].
Can anyone help clear this up for me?
In class we were deriving with the radial equations of a hydrogen atom, and in one of the equations was the commutator term:
[tex]\left[ \frac{d}{d\rho}, \frac{1}{\rho}\right][/tex]
my attempt was:
[tex]\left[ \frac{d}{d\rho}, \frac{1}{\rho}\right][/tex]
=
[tex]\left(\frac{d}{d\rho} \cdot \frac{1}{\rho}\right) - - \left(\frac{1}{\rho} \cdot \frac{d}{d\rho}\right) = 2\left(\frac{d}{d\rho}\frac{1}{\rho}\right) = \frac{-2}{\rho^{2}}[/tex]
I know above is incorrect, but how is this commutator calculated? For some reason when I try, I get the wrong result, but I'm confused on exactly how to do it.
Also, I am confused on how to accept that the complex conjugate of [tex]\frac{d}{d\rho} = \frac{-d}{d\rho}[/tex].
Can anyone help clear this up for me?