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Doc Al

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when i mentioned that i understand the math, the examples given usually has numbers in it like y = 3x+2 but in my case i only have the x and y values, so which formula should i actually use? thanks.

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Doc Al

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That's the slope-intercept form of the equation for a line: y = mx + b, where m is slope and b is the y-intercept. (Look it up!)when i mentioned that i understand the math, the examples given usually has numbers in it like y = 3x+2

Start by finding the slope.but in my case i only have the x and y values, so which formula should i actually use?

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osilmag

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Find the slope connecting those two points (y2-y1/x2-x1). The perpendicular line is the negative inverse.

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If the equation of your two points are y = mx+b, the perpendicular line to that will be every line that is

y = -(1/m)x+n where n ∈ ℝ

(Since you only care about if they are perpendicular or not and the line streches infinitely)

y = -(1/m)x+n where n ∈ ℝ

(Since you only care about if they are perpendicular or not and the line streches infinitely)

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So, if you have a line where m=2, the slope of a line perpendicular to that line would be m=-1/2.

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PeterO

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If you have the equation of a line it is pretty simple to find a couple of points on that line.

when i mentioned that i understand the math, the examples given usually has numbers in it like y = 3x+2 but in my case i only have the x and y values, so which formula should i actually use? thanks.

If you have a couple of points on the line, it is pretty simple to find the equation of that line.

So whether you are starting from the equation o f the line or a couple of points on the line, there is only one extra step to the problem.

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Doc Al

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Use the definition of slope, which was given in an earlier post. Or just look it up! https://en.wikipedia.org/wiki/Slopeand so now i need to find the slope of this line

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Doc Al

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As explained above, given two points you can find the equation of the line that connects them. But there is an infinite number of lines perpendicular to that one. Do you want that perpendicular line to intersect the first line at some particular point? Up to you!

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