NafeesAhmed Messages 6 Reaction score 0 Thread starter Apr 6, 2013 #1 Homework Statement A runner is rises up by 4.5 meters in 3.5 seconds, what average power must be consumed? Homework Equations P=w/t w=F.d The Attempt at a Solution p=4.5/3.5= 1.28 watt
Homework Statement A runner is rises up by 4.5 meters in 3.5 seconds, what average power must be consumed? Homework Equations P=w/t w=F.d The Attempt at a Solution p=4.5/3.5= 1.28 watt
Zatman Messages 85 Reaction score 0 Apr 6, 2013 #2 Average power is work done divided by time taken, as you've correctly written: P = W/t. But you have substituted in a distance for W; this is incorrect, W is the work done and is measured in joules. What has the runner done work against? What type of energy has changed?
Average power is work done divided by time taken, as you've correctly written: P = W/t. But you have substituted in a distance for W; this is incorrect, W is the work done and is measured in joules. What has the runner done work against? What type of energy has changed?
NafeesAhmed Messages 6 Reaction score 0 Apr 6, 2013 #3 thats exactly what i wanted to ask, as we know w=f.d here we can use d=4.5m but what about F?
Zatman Messages 85 Reaction score 0 Apr 6, 2013 #4 What force is acting on the runner (there's only one :) )? I've just realized there's no mass - you can't get a numerical answer without knowing the mass of the runner. Did you not get given a value for the mass?
What force is acting on the runner (there's only one :) )? I've just realized there's no mass - you can't get a numerical answer without knowing the mass of the runner. Did you not get given a value for the mass?