How to Calculate EMF and Internal Resistance in a Circuit?

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SUMMARY

The discussion focuses on calculating the Electromotive Force (EMF) and internal resistance (Ri) of a cell using two scenarios involving resistors. In the first scenario, a cell supplies 1.2A through two 2-ohm resistors in parallel and 0.4A when connected in series. The second scenario involves a 2-ohm resistor in series with a current of 0.25A, which increases to 0.3A when a second 2-ohm resistor is added in parallel. The equations derived from these scenarios are essential for solving for EMF and Ri.

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  • Study the principles of series and parallel circuits
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Homework Statement


Hi, my first post here. :smile:
Anyway I am struggling with this homework, can someone help me out, show me what to do please.

1)a cell can supply a current of 1.2A through two 2ohm resistors connected in parallel. When they are connected in series the value of the current is 0.4A. calculate the EMF and the internal resistance of the cell.

2) A cell is joined in series with a resistance of 2ohms and a current of 0.25A flows through it. When a second resistance of 2ohms is connected in parallel with the first the current through the cell increases to 0.3A. What is the EMF, and what is the internal resistance of the cell?

I really have no idea what to do, but i need to do this very quickly.

Any help would be greatly appreciated
 
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a cell can supply a current of 1.2A through two 2ohm resistors connected in parallel.

EMF = 1.2 ( 1 Ohm + Ri )

When they are connected in series the value of the current is 0.4A

You write the equation.

Two equations and two unknown variables ( Ri and EMF ). Solve !
 

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