How to Calculate Force Exerted on Rain Gauge Lid per ml of Rain Water?

AI Thread Summary
To calculate the force exerted on the lid of a rain gauge per milliliter of rainwater, one must consider the buoyant force acting on the float, which is influenced by the volume of water collected. The float, with a diameter of 12 cm and a volume of 1 liter, will rise as water fills the vessel, exerting an upward force on the lid that equals the buoyant force. The key challenge lies in determining the depth of water in the space between the float and the collection vessel for every milliliter of rainwater added. As the vessel fills, while the force on the lid will vary, the force per milliliter will remain constant, represented as the slope of a line. Understanding these dynamics is crucial for accurate calculations in this buoyant force problem.
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Homework Statement



The .png file attached shows a simple rain gauge where rain water is collected through a funnel of 25cm diameter. As water flows through the sides of the vessel and it fills the vessel it exerts an upward force on the bottom surface of the float. This force is transmitted to the top lid of the vessel(not shown in fig.). Given diameter of the collecting vessel is 13cm and that of the float is 12cm, calculate the force that will be exerted on the lid of the vessel per ml of rain water collected. Neglect weight of the float. Given: volume of float= 1 litre.



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The Attempt at a Solution



I have calculated the height of the float and found it to be 8.84cm.
(Since volume of float is 1litre= 0.001m^3 and dia of float is 12cm, we can find volume)
After this I am confused as to what to do since the water which will pour into the vessel will fill up and push the float upward till it comes in contact with the lid. This means a force will be exerted on the lid and which is to be calculated. How will this vary with increase per ml of rain water filled? Please help!
 

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Is the float filled with air? Can we neglect the weight of the float? Is the float made of a light weight material like Styrofoam? This is a buoyant force problem.
 
Yes, the weight of the float can be neglected.
 
It turns out that none of the questions I asked above is relevant to the problem. Essentially you have a float that wants to ride on top of the water but can't because there is a lid keeping it against the bottom of the collection vessel. The force pushing down on the lid will equal to the Buoyant force trying to push the force up. The rain water can only fill the volume between the float and collection vessel. You will need to find out how to calculate the buoyant force of a floating object. The challenge is determining the depth of water in the space between the float and collection vessel for every 1 ml of rain water. The force will indeed change as the vessel fills up but F/ml will be a constant (actually the slope of a line).
 

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