I How to calculate incident light on surface with multiple orientations?

  • I
  • Thread starter Thread starter Jman99
  • Start date Start date
AI Thread Summary
To calculate the incident light intensity on a surface with multiple orientations, one must consider both the vertical and horizontal tilt angles. The intensity can be determined by multiplying the known intensity by the cosines of the angles of incidence. In this scenario, with a 45-degree vertical tilt and a 22-degree horizontal rotation, the projected area plays a crucial role in assessing light energy flux. The discussion emphasizes the importance of accurately accounting for these angles to achieve precise calculations. Understanding the relationship between angle and intensity is key to determining the effective light energy on the surface.
Jman99
Messages
3
Reaction score
0
Lets say you have a light source with a uniform beam of known intensity per meter square incident on a surface and the surface is tilted both vertically and horizontally.
The surface is on a platform and tilted directly up and the angle of incidence is 45 degrees while the platform is also rotated horizontally at 22 degrees (angle of incidence 22 degrees here?).
How to calculate the intensity? Is it just multiplying both the cosines of each angles by the intensity?
 
Physics news on Phys.org
Jman99 said:
Is it just multiplying both the cosines of each angles by the intensity?
A good indication of the light energy flux would be the projected area - i.e. what you suggest.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top