How to Calculate Maximum Jump Height with Given Variables

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SUMMARY

The maximum jump height for a 73 kg high jumper with an initial vertical velocity of 7.6 m/s can be calculated using the conservation of energy principle. The relevant equation is mgh1 + 1/2mv1^2 = mgh2 + 1/2mv2^2, where at the peak of the jump, the final velocity (v2) is zero. By substituting v2 with 0, the equation simplifies to allow for the calculation of height (h2) based on the initial conditions and gravitational acceleration of 9.8 m/s².

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  • Understanding of conservation of energy principles in physics
  • Familiarity with kinematic equations
  • Basic algebra for solving equations
  • Knowledge of gravitational acceleration (9.8 m/s²)
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  • Learn how to apply kinematic equations to vertical motion problems
  • Explore the effects of mass on jump height in different gravitational fields
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Homework Statement



A 73 kg high jumper leaves the ground with a vertical velocity of 7.6 m/s.
How high can he jump? The acceleration of gravity is 9.8 m/s^2.


Homework Equations



mgh1 + 1/2mv1^2 = mgh2 + 1/2mv2^2

The Attempt at a Solution



0 + 1/2(7.6)^2 = 9.8(h2) + 1/2(v2)^2

How can you solve this when you two unknowns?
Does v1 = 7.6 also apply to v2?
Am I using the right equation?
 
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Correct equation...Concept:when the jumper has jumped his highest at that point "instantaneously" his velocity becomes zero..So set v2=0 and head on with the math.
 
Alright thank you, that helps a ton.
 

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