How to Calculate Minimum Height for Safe Parachute Deployment

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To calculate the minimum height for safe parachute deployment, the skydiver must decelerate from a terminal velocity of 65 m/s to a safe landing speed of 5 m/s. The parachute provides a deceleration of 30 m/s², but gravity also accelerates the skydiver at 9.81 m/s², which must be factored into the calculations. Using the kinematic equation v² = u² + 2as, the net acceleration is determined by combining the deceleration from the parachute and the acceleration due to gravity. The correct minimum height for parachute deployment is calculated to be 104 meters, as opposed to the incorrect initial estimates of 70 meters. Understanding these dynamics is crucial for ensuring a safe landing.
stupif
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1. a free falling skydiver reaches a terminal velocity of 65m/s before opening his parachute.the parachute can provide a deceleration of 30m/[s[2]. a parchutist cannot hit the ground at a speed greater than 5m/s without risking injury. what is the minimum height at which the skydiver can open his parachute?


2. anyone can gives me some guidelines to do this question. because i don't understand what the question talking about. i don't know where i should start.



The Attempt at a Solution

 
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Basically they want you to calculate from what height your final velocity will be 5m/s, assuming an initial velocity of 65m/s and an acceleration of -30m/s.
 
i used this formula [v[/2] = 2] + 2as
but my answer 70m. the answer is 104m.
then how?
 
I get 70m too. Might be a mistake in the answers?
 
Hi stupif! Welcome to PF! :smile:

@Nayfie: I like your drawing! :wink:

And it's nice that the parachute gives a deceleration of 30 m/s2, but did you consider that gravity still accelerates you down with 9.81 m/s2?
 
Last edited:
I like Serena said:
@Nayfie: I like your drawing! :wink:
I'm glad somebody liked it, it took me a lot longer than you'd think! :P

I like Serena said:
did you consider that gravity still accelerates you down with 9.81 m/s2?

I need more sleep. I think my brain has melted from exam study. :)
 
nayfie said:
I'm glad somebody liked it, it took me a lot longer than you'd think! :P

I'm not telling how long it took me to make the drawing for Lajka! :-p
But I enjoyed making it!


nayfie said:
I need more sleep. I think my brain has melted from exam study. :)

Well get some sleep and report back! :smile:
 
so how to solve this question~i think about it day and night~haha
 
  • #10
Okay. I'll summarize everything we know and then you should be able to work this out.

g \approx 9.81ms^{-2}
a_{parachute} = -30ms^{-2}
v_{0} = 65ms^{-1}
v_{f} = 5ms^{-1}

The net acceleration will be a_{parachute} + g. Notice that the acceleration of gravity is in opposite direction to the acceleration of the parachute.

This leaves you with one unknown. The distance over which this acceleration needs to act to slow you down from 65ms^{-1} to 5ms^{-1}.

You have a formula to do this.

:)
 
  • #11
thank you very much~i got it
 

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