How to Calculate Potential Energy Difference for a Dipole in an Electric Field?

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Homework Statement


A molecule of water has a dipole moment of 6.1×10–30 C m. Calculate the difference in potential energy between when its dipole is parallel to an electric field of 2.0×105 V m–1 and when it is anti-parallel to the field.


Homework Equations


U=kq1q2/r
V=U/q
V=Ex


The Attempt at a Solution


If the charge on each side of the dipole is just 1.6x10-19 ill be able to do the problem i think. other than that i have no idea what to do.
i was guna divide the dipole moment by 1.6x10-19 to give me the diameter of the molecule. then just use U=kq1q2/r

Help me please and add any helpful infomation

Thankyou
 
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Investigate dipole moments in electric fields, and in particular the torque that obtains for a given angle of the dipole moment vector to the electric field vector.