How to Calculate Quantum Tunneling Probability for an Electron?

Click For Summary
SUMMARY

The discussion focuses on calculating the quantum tunneling probability for an electron encountering a potential barrier defined by V(x) = 0 for x<0 and x>d, and V(x) = V_{0} for 0 PREREQUISITES

  • Understanding of quantum mechanics principles, specifically quantum tunneling.
  • Familiarity with the Schrödinger equation and its applications.
  • Knowledge of wave functions and boundary conditions in quantum systems.
  • Basic concepts of potential barriers in quantum physics.
NEXT STEPS
  • Study the solution of the Schrödinger equation in piecewise potential scenarios.
  • Learn about boundary conditions and their application in quantum mechanics.
  • Explore the concept of wave function normalization in quantum systems.
  • Investigate the implications of quantum tunneling in semiconductor physics.
USEFUL FOR

Students of quantum mechanics, physicists working with quantum tunneling phenomena, and researchers in semiconductor technology will benefit from this discussion.

iAlexN
Messages
16
Reaction score
0

Homework Statement


A particle with the energy E < V_{0} (V_{0} > 0) moves in the potential V(x) = 0, x<0 ; V(x)= V_{0}, 0<x<d and V(x)= 0, x>d. Measure the probability that the particle will tunnel through the barrier by calculating the absolute value of the ratio squared, |\Psi(d)/\Psi(0)|^{2} between the values of the wave function at x=d and x = 0

Calculate the probability for an electron, when V_{0}- E=1 eV and d = 1 Å.

Homework Equations


\Psi(x) = ae^{\kappa*x}+be^{-\kappa*x}, \kappa = \sqrt{2m( V_{0}-E)/\hbar^{2}} for E<V_{0}

The Attempt at a Solution



Firstly I get:

\kappa = \sqrt{2m(1)/\hbar^{2}} for E<V_{0}

However, the problem is with this wave function:

\Psi(x) = ae^{\kappa*x}+be^{-\kappa*x}

In order to calculate the ratio, |\Psi(d)/\Psi(0)|^{2}, I think I have to define a and b somehow, but I don't know where to start.

Thanks!
 
Physics news on Phys.org
You have to solve Shroedinger's equation in all three regions. Then you need to apply the appropriate boundary conditions.
 

Similar threads

Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K